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javax.servlet.ServletException : Could not resolve view with name 'home' in servlet with name 'appServlet'

转载 作者:行者123 更新时间:2023-11-29 05:05:34 56 4
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我遇到了这个错误:

javax.servlet.ServletException: Could not resolve view with name 'home' in servlet with name 'appServlet'

这是我的 servlet-context.jsp

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd">

<import resource="classpath:di-context.xml"/>
<!-- DispatcherServlet Context: defines this servlet's request-processing
infrastructure -->
<!-- Register the welcome.properties -->
<bean id="messageSource" class="org.springframework.context.support.ReloadableResourceBundleMessageSource">
<property name="basename" value="classpath:messages"/>
<property name="defaultEncoding" value="UTF-8"/>
</bean>

<bean id="localeChangeInterceptor" class="org.springframework.web.servlet.i18n.LocaleChangeInterceptor">
<property name="paramName" value="lang"/>
</bean>

<bean id="localeResolver" class="org.springframework.web.servlet.i18n.CookieLocaleResolver">
<property name="defaultLocale" value="en_US"/>
</bean>
<!--class="org.springframework.web.servlet.i18n.AcceptHeaderLocaleResolver" />-->

<bean id="handlerMapping" class="org.springframework.web.servlet.mvc.support.ControllerClassNameHandlerMapping">
<property name="interceptors">
<ref bean="localeChangeInterceptor"/>
</property>
</bean>

<mvc:interceptors>
<bean class="org.springframework.web.servlet.i18n.LocaleChangeInterceptor">
<property name="paramName" value="lang" />
</bean>
</mvc:interceptors>

<!-- <bean id="messageSource" class="org.springframework.context.support.ReloadableResourceBundleMessageSource">
<property name="basename" value="WEB-INF/classes/messages" /> </bean> -->
<!-- Enables the Spring MVC @Controller programming model -->
<mvc:annotation-driven/>

<!-- Handles HTTP GET requests for /resources/** by efficiently serving
up static resources in the ${webappRoot}/resources directory -->
<mvc:resources mapping="/resources/**" location="/resources/"/>

<context:component-scan base-package="ru.blogspot.feomatr.controller"/>

<!-- Resolves views selected for rendering by @Controllers to .jsp resources
in the /WEB-INF/views directory -->
<!-- beans:bean class="org.springframework.web.servlet.view.InternalResourceViewResolver" -->
<bean id="tilesViewResolver" class="org.springframework.web.servlet.view.UrlBasedViewResolver">
<property name="viewClass" value="org.springframework.web.servlet.view.tiles3.TilesView"/>
</bean>
<bean id="tilesConfigurer" class="org.springframework.web.servlet.view.tiles3.TilesConfigurer">
<property name="definitions">
<list>
<value>/WEB-INF/layouts/layouts.xml</value>
<!-- Scan views directory for tiles configuration -->
<value>/WEB-INF/views/**/views.xml</value>
</list>
</property>
</bean>
<bean id="validator" class="org.springframework.validation.beanvalidation.LocalValidatorFactoryBean"/>
</beans>

这是我的 web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">

<!-- The definition of the Root Spring Container shared by all Servlets
and Filters -->
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
/WEB-INF/spring/root-context.xml
/WEB-INF/spring/security.xml
classpath:di-context.xml
</param-value>
</context-param>

<!-- Creates the Spring Container shared by all Servlets and Filters -->
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>

<!-- Processes application requests -->
<servlet>
<servlet-name>appServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/appServlet/servlet-context.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>

<servlet-mapping>
<servlet-name>appServlet</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>

<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>

</web-app>

我的家

@RequestMapping(value = {"/home", "/"}, method = RequestMethod.GET)
public String showHome(Model model) {
log.info("showHome");
return "home";
}

是的,我在路径 src/main/webapp/WEB-INF/views 中有文件 home.jsp我无法修复它,有人可以帮助我吗?

最佳答案

像这样更改您的请求映射..

@RequestMapping(value = "/home", method = RequestMethod.GET)
public String showHome(Model model) {
log.info("showHome");
return "home";
}

并将其添加到您的 spring-servlet.xml..

<bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="viewClass" value="org.springframework.web.servlet.view.JstlView" />
<property name="prefix" value="/WEB-INF/views/" />
<property name="suffix" value=".jsp" />
</bean>

关于javax.servlet.ServletException : Could not resolve view with name 'home' in servlet with name 'appServlet' ,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/30497301/

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