iOS - 将变量分配给 cellForRowAtIndexPath 中对象的属性

Question

我有一个 SQL 数据库，其中包含每天营业时间/天数的商店。我计算今天的日期，并希望在自定义单元格中包含属性值。

NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:@"dd"];
int day = [[dateFormatter stringFromDate:[NSDate date]] intValue];

switch (day) {
    case 1:
        openingsDag = @"open_ma"; 
        break;
    case 2:
        openingsDag = @"open_di";
        break;
    case 3:
        openingsDag = @"open_woe";
        break;
    case 4:
        openingsDag = @"open_do";
        break;
    case 5:
        openingsDag = @"open_vr";
        break;
    case 6:
        openingsDag = @"open_za";
        break;
    case 7:
        openingsDag = @"open_zo";
        break;
    default: 
        break;
}

在 cellForRowAtIndexPath 中，我将属性值分配给可变数组中的标签:

cell.naamLabel.text = [[winkelArray objectAtIndex:indexPath.row] naam];
cell.openingsLabel.text = [[winkelArray objectAtIndex:indexPath.row] openingsDag];

这似乎不起作用，我尝试了其他几种方法(stringWithFormat，cell.openingsLabel而不是cell.openingsLabel.text，...)来获取标签中的数据，但似乎无法正确处理.

Answer 1

我计算日期的方法是正确的，但我的返回类型不...

-(NSString*)berekenOpeningdag:(Winkel*)w {
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:@"ee"];
int day = [[dateFormatter stringFromDate:[NSDate date]] intValue];

NSString *openingsUrenReturn = @"";


switch (day) {
    case 1:
        openingsUrenReturn = w.open_ma;
        break;
    case 2:
        openingsUrenReturn = w.open_di;
        break;
    case 3:
        openingsUrenReturn = w.open_woe;
        break;
    case 4:
        openingsUrenReturn = w.open_do;
        break;
    case 5:
        openingsUrenReturn = w.open_vr;
        break;
    case 6:
        openingsUrenReturn = w.open_za;
        break;
    case 7:
        openingsUrenReturn = w.open_zo;
        break;
    default: 
        break;
}
return openingsUrenReturn;

在那里，我回答了我自己的问题!