gpt4 book ai didi

objective-c - 错误-[NSIndexPath 发布] : message sent to deallocated instance 0x6a9d790

转载 作者:行者123 更新时间:2023-11-29 04:50:22 25 4
gpt4 key购买 nike

我使用自定义单元格创建 tableView。这是单元格 .h 文件的代码

@interface ZUITableViewCell : UITableViewCell {
IBOutlet UITextField *_textFieldOutlet;
IBOutlet UILabel *_textLabelOutlet;

}
@property (retain, nonatomic) IBOutlet UITextField *_textFieldOutlet;
@property (retain, nonatomic) IBOutlet UILabel *_textLabelOutlet;

@end

在我的表格 View Controller 文件中我创建了这个

#import <UIKit/UIKit.h>
#import "ZUITableViewCell.h"

@protocol ZUITableViewControllerDelegate ///for main view controller

-(void) doneButtonPressed;

@end

@interface ZUITableViewController : UITableViewController {
id <ZUITableViewControllerDelegate> delegate;

NSMutableArray *menuItems;
BOOL isAddingFields;
}

@property (nonatomic, retain) NSArray *menuItems;
@property (nonatomic, assign) id<ZUITableViewControllerDelegate> delegate;

- (CGRect) GetCellHegiht: (ZUITableViewCell *) cell;

@end

当用户选择第二行时,我想在 TableView 中添加新行。为此,我描述了这个方法

- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath
{
// Navigation logic may go here. Create and push another view controller.
/*
<#DetailViewController#> *detailViewController = [[<#DetailViewController#> alloc] initWithNibName:@"<#Nib name#>" bundle:nil];
// ...
// Pass the selected object to the new view controller.
[self.navigationController pushViewController:detailViewController animated:YES];
[detailViewController release];
*/
NSLog (@"row = %d", indexPath.row);
NSLog(@"INIT %p", self);
ZUITableViewCell *cell = [tableView cellForRowAtIndexPath:indexPath];
[cell._textFieldOutlet becomeFirstResponder];
if (indexPath.row == 1 && isAddingFields == FALSE) {
isAddingFields = TRUE;
[menuItems insertObject:@"CC" atIndex:1];
[menuItems insertObject:@"BCC" atIndex:2];

NSIndexPath *path1 = [NSIndexPath indexPathForRow:1 inSection:0];
NSIndexPath *path2 = [NSIndexPath indexPathForRow:2 inSection:0];
NSArray *indexArray = [NSArray arrayWithObjects:path1,path2,nil];
[tableView insertRowsAtIndexPaths:indexArray withRowAnimation:UITableViewRowAnimationTop];
[tableView reloadRowsAtIndexPaths:[NSArray arrayWithObject:indexPath] withRowAnimation:UITableViewRowAnimationFade];

[path1 release];
[path2 release];

[cell._textFieldOutlet becomeFirstResponder];
}
}

这是我的 cellForRowAtIndexPath 方法

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
static NSString *CellIdentifier = @"Cell";
NSLog(@"INIT %p", self);
NSLog (@"cell for row = %d", indexPath.row);
ZUITableViewCell *cell = (ZUITableViewCell *)[tableView dequeueReusableCellWithIdentifier:CellIdentifier];
if (cell == nil) {
NSArray *topLevelsObjects = [[NSBundle mainBundle] loadNibNamed:@"ZUITableViewCell" owner:nil options:nil];
for (id currentObject in topLevelsObjects){
if ([currentObject isKindOfClass:[UITableViewCell class]]){
cell = (ZUITableViewCell *) currentObject;
break;
}
}
}
if (indexPath.row == 3 && isAddingFields == FALSE){
// [cell setBounds:[self GetCellHegiht:cell]];
}
cell.selectionStyle = UITableViewCellSelectionStyleNone;
cell._textLabelOutlet.text = [menuItems objectAtIndex:indexPath.row];
cell._textFieldOutlet.tag = indexPath.row;
[cell._textFieldOutlet setEnabled:YES];
if(indexPath.row == 0){
[cell._textFieldOutlet becomeFirstResponder];
}


return cell;
}

在 Debug模式下,我可以在单击indexPath.row == 1的行后看到,该 Controller 使用indexPath.row = 1和2调用cellForRowAtIndexPath方法两次。但是After It Controller 调用方法

- (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section
{
//#warning Incomplete method implementation.
return [menuItems count];
}

再次调用 cellForRowAtIndexPath 方法,程序出现此错误后(我启用僵尸)错误 -[NSIndexPath release]:消息发送到已释放实例 0x6a9d790

最佳答案

方法[NSIndexPath indexPathForRow:inSection:](在path1和path2中使用)返回一个自动释放的对象,之后不需要调用release

关于objective-c - 错误-[NSIndexPath 发布] : message sent to deallocated instance 0x6a9d790,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/8952406/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com