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mysql - MySql 选择所需的指导

转载 作者:行者123 更新时间:2023-11-29 04:49:26 25 4
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你好,我有一张这样的 table

Activity     Date
---------------------
0 2012-11-20
1 2012-11-20
1 2012-11-20
1 2012-11-21
1 2012-11-21
0 2012-11-22

我需要选择记录为

 Day-wise total   0's    1's    Date  
------------------------------------------
3 1 2 2012-11-20
2 0 2 2012-11-21
1 1 0 2012-11-22

最佳答案

您需要的是一个GROUP BY dateCOUNT(Activity) 来获取每日总计和一个CASE 表达式来转换1 和 0 的值。我在这里使用了 SUM 但它的行为就像 COUNT 一样:

SELECT
COUNT(Activity) AS "Day-wise total",
SUM(CASE WHEN Activity = 0 THEN 1 ELSE 0 END) AS "0's",
SUM(CASE WHEN Activity = 1 THEN 1 ELSE 0 END) AS "1's",
`Date` AS "Date"
FROM Table
GROUP BY `Date`;

SQL Fiddle Demo

关于mysql - MySql 选择所需的指导,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/13510354/

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