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iPhone : JSON message not creating correctly

转载 作者:行者123 更新时间:2023-11-29 04:47:00 25 4
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我使用了以下代码:

    [dict setObject:[NSString stringWithFormat:@"%d",1] forKey:@"res_id"];


//[dict setObject:categoryId forKey:@"category"];
NSArray * values = [cartDict allValues];

NSString *request1 = [dict JSONRepresentation];
NSLog(request1);
NSDictionary *req = [NSDictionary dictionaryWithObject:dict forKey:@""];

//convert object to data
NSData *jsonData = [NSData dataWithBytes:[request1 UTF8String] length:[request1 length]];


//print out the data contents
NSString *json1 = [[NSString alloc] initWithData:jsonData
encoding:NSUTF8StringEncoding];

NSLog(@"JSON>>>>>%@",json1);

最佳答案

兄弟你的代码太乱了尝试这个简单的例子希望你能明白你的想法。它正在打印您需要的相同内容

NSMutableDictionary *cartDict = [[NSMutableDictionary alloc] init];
[cartDict setObject:[NSString stringWithFormat:@"%@",@"tId"] forKey:@"id"];
[cartDict setObject:[NSString stringWithFormat:@"%@",@"tname"] forKey:@"menuname"];
[cartDict setObject:[NSString stringWithFormat:@"%@",@"tprice"] forKey:@"price"];
[cartDict setObject:[NSString stringWithFormat:@"%@",@"tquan"] forKey:@"quantity"];
NSArray *array = [NSArray arrayWithObject:cartDict];
NSMutableDictionary *dict = [[NSMutableDictionary alloc] init];
[dict setObject:[NSString stringWithFormat:@"%@",@"personName"] forKey:@"customerName"];
[dict setObject:[NSString stringWithFormat:@"%@",@"emailid"] forKey:@"cusmailaddress"];
[dict setObject:[NSString stringWithFormat:@"%d",1] forKey:@"res_id"];
[dict setObject:array forKey:@"Order Details"];
NSLog(@"%@",dict);

关于iPhone : JSON message not creating correctly,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/9483872/

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