java - 如何在 Java 中使用 DOTALL 捕获到最后一行结尾的所有内容

Question

我有一个字符串如下:

Acid Exposure (pH)      Total
            Total   Normal

        Clearance pH  :  Channel 7
        Number of Acid Episodes 26  
        Time    31.5 min    
        Percent Time    7.4%    
        Mean Acid Clearance Time    73 sec  
        Longest Episode 7.1 min

        Gastric pH  :  Channel 8
        Time pH<4.0 425.9 min



    Bolus Exposure (Impedance)      Total
            Total   Normal

        Acid Time   22.0 min    
        Acid Percent Time   5.2%    
        Nonacid Time    6.1 min 
        Nonacid Percent Time    1.4%    
        All Reflux Time 28.2 min    
        All Reflux Percent Time 6.6%    
        Median Bolus Clearance Time 16 sec  
        Longest Episode 7.8 min

我想捕获 Acid Exposure 中的所有内容至 Time pH<包括 Time pH< 线上的所有内容所以我最终得到:

Acid Exposure (pH)      Total
            Total   Normal

        Clearance pH  :  Channel 7
        Number of Acid Episodes 26  
        Time    31.5 min    
        Percent Time    7.4%    
        Mean Acid Clearance Time    73 sec  
        Longest Episode 7.1 min

        Gastric pH  :  Channel 8
        Time pH<4.0 425.9 min

我试图捕捉到这一点的方式是:

Pattern my_pattern = Pattern.compile("Acid Exposure.*?Time pH.*?$",Pattern.DOTALL);

但是我运气不好。我也尝试添加 Pattern.DOTALL|Pattern.MULTILINE但也没有运气

Answer 1

您可以使用:

Pattern my_pattern = Pattern.compile("Acid Exposure.*?Time pH<[^\\n]*", Pattern.DOTALL);

[^\n]*在 Time pH< 之后将匹配到行尾。

RegEx Demo