ios - 当用户在横向模式下翻转 iDevice 时，如何保持 rollY 一致？

Question

在我的应用程序中，我将游戏设置为横向模式，允许用户能够翻转设备，游戏自动旋转以匹配角度。当用户将设备向右倾斜时，英雄将向右移动，向左倾斜时，英雄将向左移动。

我已经解决了这部分问题，但是当用户翻转 iDevice 时(由于耳机插孔或扬声器的位置)，问题就出现了，应用程序会自动旋转，但 rollY 正在设置英雄的位置.x 要反转。向左倾斜使英雄向右移动，向右倾斜使英雄向左移动。在查看 iDevice 翻转时 AccelY 值的 NSLogs 后，旋转时似乎无法反转position.x？

我想这更像是一个数学问题。

这是我的代码:

-(void)accelerometer:(UIAccelerometer *)accelerometer didAccelerate:(UIAcceleration *)acceleration
{
#define kFilteringFactor 0.75
    static UIAccelerationValue rollingX = 0, rollingY = 0, rollingZ = 0;

    rollingX = (acceleration.x * kFilteringFactor) + (rollingX * (1.0 - kFilteringFactor));
    rollingY = (acceleration.y * kFilteringFactor) + (rollingY * (1.0 - kFilteringFactor));
    rollingZ = (acceleration.z * kFilteringFactor) + (rollingZ * (1.0 - kFilteringFactor));

    float accelX = rollingX;
    float accelY = rollingY;
    float accelZ = rollingZ;

    NSLog(@"accelX: %f, accelY: %f, accelZ: %f", accelX, accelY, accelZ);

    CGSize winSize = [CCDirector sharedDirector].winSize;
#define kRestAccelX 0.6
#define kShipxMaxPointsPerSec (winSize.height * 1.0)
#define kMaxDiffX 0.2

#define kRestAccelY 0.0
#define kShipyMaxPointsPerSec (winSize.width * 0.5)
#define kMaxDiffY 0.2

    float accelDiffX = kRestAccelX - ABS(accelX);
    float accelFractionX = accelDiffX / kMaxDiffX;
    float pointsPerSecX = kShipxMaxPointsPerSec * accelFractionX;

    float accelDiffY = -accelY;
    float accelFractionY = accelDiffY / kMaxDiffY;
    float pointsPerSecY = kShipyMaxPointsPerSec * accelFractionY;

    _shipPointsPerSecX = pointsPerSecY;
    _shipPointsPerSecY = pointsPerSecX;

    CCLOG(@"accelX: %f, pointsPerSecX: %f", accelX, pointsPerSecX);
    CCLOG(@"accelY: %f, pointsPerSecY: %f", accelY, pointsPerSecY);
}

-(void)updateShipPos:(ccTime)dt
{
    CGSize winSize = [CCDirector sharedDirector].winSize;

    float maxX = winSize.width - _ship.contentSize.width;
    float minX = _ship.contentSize.width / 2;

    float maxY = winSize.height - _ship.contentSize.height / 2;
    float minY = _ship.contentSize.height / 2;

    float newX = _ship.position.x + (_shipPointsPerSecX * dt);
    float newY = _ship.position.y + (_shipPointsPerSecY * dt);

    newX = MIN(MAX(newX, minX), maxX);
    newY = MIN(MAX(newY, minY), maxY);

    _ship.position = ccp(newX, newY);
}

我的想法是，我试图使pointsPerSecY在向右倾斜时为正，在向左倾斜时为负。问题是，当用户翻转设备时，由于设备被翻转，它们会被颠倒。有没有办法让它在横向翻转时无论方向如何，向右倾斜时保持正值，向左保持负值？

Answer 1

做这样的事情怎么样？

if ([[UIApplication sharedApplication] statusBarOrientaion]==UIInterfaceOrientationLandscapeLeft) {
    pointsPerSecY *= -1;
}