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Java ArrayList Contains()方法不起作用

转载 作者:行者123 更新时间:2023-11-29 04:41:51 24 4
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我毫不怀疑 contains() 方法工作正常,但显然我做错了什么。我正在开发一个 android 应用程序,我正在检测 WiFi 并将 WiFi 列在 listView 中。我试图过滤掉重复出现的同一接入点,因此我创建了一个数组来跟踪重复项。这是我的代码:

public void getWifi(){

ListView wifiList = (ListView)findViewById(R.id.listView);

WifiManager wifiManager = (WifiManager) getSystemService(Context.WIFI_SERVICE);
List<ScanResult> apList = wifiManager.getScanResults();
wifiManager.startScan();

List<String> wifees = new ArrayList<>();

//split info into arrays
for(int i=0; i < apList.size(); i++){

String[] daList = String.valueOf(apList.get(i)).split(",");

String info = "";
List<String> SSIDs = new ArrayList<>();

for (String listItem : daList) {
String topic = String.valueOf(listItem.split(":")[0]);
String val = listItem.split(":")[1];
Log.d(TAG, topic);
if (Objects.equals(topic, "SSID")) {
if(SSIDs.contains(val)){
Log.d(TAG, "CONTAINS");
break;
} else {
SSIDs.add(val);
info = val;
}
} else if (Objects.equals(topic, " level")){
String strength = "";
if (Integer.parseInt(val.substring(1)) >= -35) {
strength = "100%";
} else if (Integer.parseInt(val.substring(1)) <= -35 && Integer.parseInt(val.substring(1)) >= -65) {
strength = "50%";
} else {
strength = "1%";
}
info += " " + strength;
}
}
wifees.add(info);
}

assert wifiList != null;
ArrayAdapter apter = new ArrayAdapter(this, android.R.layout.simple_list_item_1, wifees);
wifiList.setAdapter(apter);
}

这是 apList 项的内容,或者我调用 apList.get(i) 时得到的内容:

SSID: SCHOOL-GUEST, BSSID: 04:04:04:04:04:04, capabilities: [ESS], level: -91, frequency: 2412, timestamp: 72500687089, distance: ?(cm), distanceSd: ?(cm), passpoint: no, ChannelBandwidth: 0, centerFreq0: 0, centerFreq1: 0, 80211mcResponder: is not supported

这是该代码的输出(大致是因为它在手机上,出于安全原因我不想包含 AP 名称):

SCHOOL-WIRELESS        100%
SCHOOL-SECURE 50%
SCHOOL-GUEST 50%
SCHOOL WIRELESS 1%
SCHOOL_WIRELESS 1%
SCHOOL-SECURE 1%
SCHOOL-GUEST 1%
bxz1872 50%
...
...
...
(so on and so forth)

如果我能得到第二个意见就好了。我觉得我错过了一些明显的东西。谢谢!

最佳答案

.contains不起作用,因为你调用List<String> SSIDs = new ArrayList<>();for(int i=0; i < apList.size(); i++){ 内.您基本上为每个循环迭代创建新的空列表。您应该在外部 for 循环之前调用它一次:

List<String> SSIDs = new ArrayList<>();
for(int i=0; i < apList.size(); i++){
...
}

关于Java ArrayList Contains()方法不起作用,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/38901978/

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