java - 试图通过 Java 中的重复减法来除法。从这往哪儿走？

Question

package sola5;

import java.util.Scanner;

public class Assign1 {

    public static void main(String[] args) {

        Scanner input = new Scanner(System.in);

        System.out.print("Enter a three digit integer: ");
        int a = input.nextInt();
        System.out.print("Now, enter a 2 digit integer: ");
        int b = input.nextInt();

        while (a > b) {
            a = a-b;        
            System.out.println();
        }
    }
}

这就是我所了解的。我的下一步是让它显示答案和余数，但我不知道该怎么做。

Answer 1

~~>Way 1

 int count=0;
  while(a>b){  
     a-=b;//similar to a = a - b
     ++count;//similar to count = count + 1;
    } 

System.out.println(a); // remainder
System.out.println(count);//quotient

~~> Way 2(Preffered)

(假设a=30 且b=4):

!使用%得到余数 (a % b) = 30 % 4 = 2;

!Using ÷ 得到你可以做的商 (int) a ÷ b = 30 ÷ 4 = 7;

Edit:

读这个很好 link由@Spektre 在评论中提供