iphone - 我必须延长哪一个类？

Question

(我正在开发一个在表格中显示聊天消息的应用程序。但是，用户无法启动此聊天，当用户收到消息时，聊天 View 将打开。因此，我编写了以下代码:

- (void) newMessageReceived:(NSMutableDictionary *)message
{
   General *general = [General sharedManager];
   NSString *firstmessage=[message objectForKey:@"msg"];
   NSString *from=[message objectForKey:@"sender"];    
   NSArray *listItems = [from componentsSeparatedByString:@"@"];
   NSString *fromsplit=[listItems objectAtIndex:0];
   general.firstmess=firstmessage;
   general.firstfrom=fromsplit;
   NSLog(@"Mensaje recibido: %@ de %@", [message objectForKey:@"msg"], fromsplit);

   ChatViewController *cvc=[[ChatViewController alloc]initWithNibName:@"Chat" bundle:nil];

   [[self navigationController]pushViewController:cvc animated:YES];
}

一切都很好，直到这里。 ChatViewController 扩展了 UITableViewController。但是，当收到消息时，我收到以下异常:

Terminating app due to uncaught exception 'NSInternalInconsistencyException', reason: '-[UITableViewController loadView] loaded the "Chat" nib but didn't get a UITableView.

然后，我尝试更改扩展为 UIViewController 的类(这样做是为了检查程序是否进入 numberOfRowsInSection 方法)，然后我收到:

Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '-[ChatViewController setTableViewStyle:]: unrecognized selector sent to instance 0x9863200'

我认为解决第一个异常可以解决我的问题。有什么帮助吗？

谢谢。

Answer 1

In the second exception i think you have called [self setTableViewStyle:] method, while   

you have made it UIViewController.

So try to call this method by tableViewOutlet.

[tableView setTableViewStyle:];

希望这对您有帮助