java - 数组向右移动，但索引 [0] 消失了

Question

我正在向右移动一个数组，但是当我这样做时我丢失了原始数组 [0]。

int innerLastIndex = innerRotorClockWise.length - 1;

String innerOldLast = innerRotorClockWise[innerLastIndex]; 

for (int i = innerLastIndex; i != 0; i--) {

    //place a holder  for first and last. 

    innerRotorClockWise[i] = innerRotorClockWise[i-1];


    innerRotorClockWise[0] = innerOldLast;

输出:

原创

[#, G, N, U, A, H]

平移 1

[H, H, G, N, U, A] 

移动 2

[A, A, H, G, N, U]

我看过其他人，他们似乎没有帮助解决这个问题。我是否也必须为我的第一个元素创建一个占位符？

Answer 1

您似乎在循环中放置了以下语句:

innerRotorClockWise[0] = innerOldLast;

这会导致第 0 个元素在第一次迭代中被替换。在第一个语句本身之后关闭循环:

for (int i = innerLastIndex; i != 0; i--) {

     innerRotorClockWise[i] = innerRotorClockWise[i-1];

}
innerRotorClockWise[0] = innerOldLast;

以下代码适用于我:

    String[] innerRotorClockWise = new String[]{"#", "G", "N", "U", "A", "H"};
    int innerLastIndex = innerRotorClockWise.length - 1;

    String innerOldLast = innerRotorClockWise[innerLastIndex];

    for (int i = innerLastIndex; i != 0; i--) {


        innerRotorClockWise[i] = innerRotorClockWise[i - 1];

    }
    innerRotorClockWise[0] = innerOldLast;
    System.out.println(Arrays.toString(innerRotorClockWise));