objective-c - Imageview 的 "touch area rect"在动画移动到其他地方后仍然保留

Question

我正在使用 CABasicAnimation 移动图像，但我注意到它的触摸事件矩形保留在原来的位置 - 如何更新矩形，使其不会在错误的位置注册？

CABasicAnimation *theAnimation; 
theAnimation=[CABasicAnimation animationWithKeyPath:@"transform.translation.x"];
theAnimation.duration=0.3;
theAnimation.repeatCount=0;
theAnimation.fillMode = kCAFillModeForwards;
theAnimation.removedOnCompletion = NO;
theAnimation.autoreverses=NO;
theAnimation.fromValue=[NSNumber numberWithFloat:0];
theAnimation.toValue=[NSNumber numberWithFloat:-rect.size.width*0.9];
[self.layer addAnimation:theAnimation forKey:@"animateLayer"];

Answer 1

在这种情况下，您需要移动 UIImageView 的 TouchImageView 子类，而不是 self.layer。后者是一个较低级别的绘图表面，但不处理触摸事件等。

来自iPad: Move UIView with animation, then move it back ，这里有一些改编的代码，可以像您一样为 translation 属性设置动画:

CGFloat moveX = -rect.size.width*0.9;
CGFloat moveY = 0;

[UIView beginAnimations: @"Move View" context:nil];
[UIView setAnimationDuration: 0.3 ];
self.transform = CGAffineTransformMakeTranslation(moveX,moveY);
[UIView commitAnimations];

但是，您应该能够通过仅更改 View 的框架来简化此操作:

CGRect newFrame = self.frame;
newFrame.x -=rect.size.width*0.9;

[UIView beginAnimations: @"Move View" context:nil];
[UIView setAnimationDuration: 0.3 ];
self.frame = newFrame;
[UIView commitAnimations];