mysql - 如何从数据库中选择得票最多的用户？

Question

我有一个接受投票的小型系统，在我的查询中，我选择投票(用户名)和该用户的总票数。我的想法是只显示拥有更多选票的用户，我知道我可以添加 ORDER BY 的查询并获得第一个值，该值将是票数最高的那个。但是我正在尝试确定两个人是否有票数。我该怎么做？

我正在使用 cgi。

my $connection = $MY_CONNECTION->prepare("SELECT voto, COUNT(*) total FROM votos  WHERE mes = 12 GROUP BY vote HAVING COUNT(*) > 0 ORDER BY COUNT(*)");
$connection->execute || print "ERROR 1";

my @resultados;
my $info = '';


while ($info = $connection->fetchrow_hashref()) {

    my $nombre   = $info->{voto};
    my $totalVotos = $info->{total};

my $winner = "";
my $temp2  = "";
my $temp   = $totalVotos ;

if ($temp2 => $temp) {
    $temp2 = $totalVotos ;
    $winner = $nombre   ; 

}


    print "<p><strong>Winner: </strong> $winner </p> "; 
    print "<hr>";
}

Answer 1

您可以通过以下方式返回获得最高票数(以及多少票)的所有人:

select voto, count(*) as total from votos
    where mes = 12
    group by voto -- I assume "vote" in your question was typo
    having total = (
        select max(ct) from (
            select voto,count(*) as ct from votos group by voto
        )
    )
    and total > 0 -- from your original but not sure it can fail
;

您也可以使用 rank() 函数。

---

在不修改 SQL 的情况下，您可以将 perl 更改为如下内容:

# ...

# initialisation shouldn't be inside while loop
my $winner = "";
my $temp2  = "";

while ($info = $connection->fetchrow_hashref()) {
    my $nombre = $info->{voto};
    my $totalVotos = $info->{total};

    if ($temp2 < $totalVotos) { # your original "=>" seems wrong
        $temp2 = $totalVotos;
        @winner = $nombre;
    elsif ($temp2 == $totalVotos) {
        push @winner, $nombre;
    }
}

# postprocessing shouldn't be inside while loop
$winner = join(", ", @winner); # or whatever
print "<p><strong>Winner: </strong> $winner </p> "; 
print "<hr>";