java - 4 小时后不应访问 Otp

Question

我写了一个通过发送otp通过电子邮件进行验证的代码。我必须以这样的方式配置，如果用户在 4 小时后输入 otp，则不应接受。我在 if 条件下使用了日期对象，它工作正常，但有什么方法可以用更少的代码实现同样的效果。

Date dateFromDatabase=emailData.getBody().getUpdated();

if((dateFromDatabase.getYear()-date.getYear())==0){

    if((dateFromDatabase.getMonth()-date.getMonth())==0){

        if((dateFromDatabase.getDay()-date.getDay())==0){
            if((dateFromDatabase.getHours()-date.getHours())<=4){
                System.out.print("May Be Right otp");

                if( emailData.getBody().getHASHCODE().equals(fromotp)){
                    System.out.print("matched");
                    emails.setId(emailData.getBody().getId());
                    emails .setVERIFIED(1);
                    emails.setHASHCODE("");
                    emails.setEmails(To);
                    //updateEmails(emails);
                    String Subject="Pharmerz Thanknote";
                    String Acknowledge="Thank you for verifying on Pharmerz";
                    email.SendMail(To,Subject,Acknowledge);
                    Emails saveEmails =emailService.create( emails );
                    return new ResponseEntity<Emails>(emails,HttpStatus.OK);

                }else{
                    System.out.print("miss matched");
                    emailService.delete(emailData.getBody().getId());
                    return new ResponseEntity<Emails>(HttpStatus.BAD_REQUEST);
                }



            }else{
                System.out.print("Wrong or Old Otp");
                emailService.delete(emailData.getBody().getId());
                return new ResponseEntity<Emails>(HttpStatus.BAD_REQUEST);
            }
        }else{
            System.out.print("Wrong or Old Otp");
            emailService.delete(emailData.getBody().getId());
            return new ResponseEntity<Emails>(HttpStatus.BAD_REQUEST);
        }

    }else{
        System.out.print("Wrong or Old Otp");
        emailService.delete(emailData.getBody().getId());
        return new ResponseEntity<Emails>(HttpStatus.BAD_REQUEST);
    }

}
else{
    System.out.print("Wrong or Old Otp");
    emailService.delete(emailData.getBody().getId());
    return new ResponseEntity<Emails>(HttpStatus.BAD_REQUEST);
}

Answer 1

试试这个:

Date currentDate = new Date();
Date dateFromDatabase = // get the date from the database

long duration  = dateFromDatabase.getTime() - currentDate.getTime();
long diffInHours = TimeUnit.MILLISECONDS.toHours(duration);

您可以使用 diffInHours 变量并执行您的业务逻辑。