php - 重命名获取的 mysql 然后编码为 JSON

Question

我想将自己的表名编码为 JSON 而不想使用 mysql 表名。如果我重命名该列，我只需要在 de php 文件中重命名它们。

简而言之:

• 运行查询
• 获取mysql
• 重命名输出中的列
• 编码成JSON

这是我现在拥有的:

while($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
    $rows['feed'] =  $row;
    sendResponse(200, json_encode($rows));
}

我想知道:如何打开抓取的数组并更改列名并重命名为我自己的名字，然后将它们发送到 JSON

编辑:我编辑了我的行

 $result = mysql_query("SELECT * FROM od_common.debiteur WHERE SORT_NAAM LIKE '%comp%'");



while($row = mysql_fetch_array($result, MYSQL_ASSOC)) {

$deb_nr = $row['DEB_NR'];
$deb_naam = $row['DEB_NAAM'];
$deb_adres = $row['DEB_ADRES'];



$rows['klant'] = array('klantnr' => $deb_nr, 'klntnm' => $deb_naam, 'adrs'      =>         $deb_adres);





sendResponse(200, json_encode($rows));
}
}

我几乎得到了我想要的。但我想要这个:

 {
   "klant": [
    {
      "klntnr": "10010",
      "klntnm": "Company1",
  "adrs": "street1"
},
{
  "klntnr": "25071",
  "klntnm": "Company2",
  "adrs": "street2"
},
{
  "klntnr": "25247",
  "klntnm": "Company3",
  "adrs": "street3"
},
{
  "klntnr": "25454",
  "klntnm": "Company4",
  "adrs": "street4"
},
{
  "klntnr": "25601",
  "klntnm": "Company5",
  "adrs": "street5"
}
  ]
 }

不是这个:

{  "klant": {
 "klantnr": "10010",
 "klntnm": "Company1",
 "adrs": "street1"
   }
  }{
  "klant": {
    "klantnr": "25071",
    "klntnm": "Company2",
    "adrs": "street2"
  }
 }{
  "klant": {
    "klantnr": "25247",
    "klntnm": "Company3",
    "adrs": "street3"
  }
 }{
   "klant": {
    "klantnr": "25454",
    "klntnm": "Company4",
    "adrs": "street4"
  }
 }{
  "klant": {
    "klantnr": "25601",
    "klntnm": "Company5",
    "adrs": "street5"
  }
 }

Answer 1

最好的办法是在源代码中修改您的查询，例如:

$result = mysql_query("SELECT columna, columnb FROM table");

到:

$result = mysql_query("SELECT columna AS 'whatever', column AS 'ha' FROM table");

---

下一个最佳想法是修改 $row 数组，但这是非常基本的 PHP。