java - 在 Android 中加密并在 CryptoJS 中解密

Question

您好，我有 Java 代码可以解密使用 CryptoJS 库 (AES) 加密的密文。现在我想编写将再次加密明文的 javacode。

请找到下面的代码。

 try {
        String secret = "René Über";
        String cipherText="U2FsdGVkX1+tsmZvCEFa/iGeSA0K7gvgs9KXeZKwbCDNCs2zPo+BXjvKYLrJutMK+hxTwl/hyaQLOaD7LLIRo2I5fyeRMPnroo6k8N9uwKk=";

        byte[] cipherData = Base64.decode(cipherText, Base64.DEFAULT);
        byte[] saltData = Arrays.copyOfRange(cipherData, 8, 16);

        MessageDigest md5 = MessageDigest.getInstance("MD5");
        final byte[][] keyAndIV = GenerateKeyAndIV(32, 16, 1, saltData, secret.getBytes("utf-8"), md5);
        SecretKeySpec key = new SecretKeySpec(keyAndIV[0], "AES");
        IvParameterSpec iv = new IvParameterSpec(keyAndIV[1]);

        byte[] encrypted = Arrays.copyOfRange(cipherData, 16, cipherData.length);
        Cipher aesCBC = Cipher.getInstance("AES/CBC/PKCS5Padding");
        aesCBC.init(Cipher.DECRYPT_MODE, key, iv);
        byte[] decryptedData = aesCBC.doFinal(encrypted);
        String decryptedText = new String(decryptedData,"utf-8");
        System.out.println("Decrypted "+decryptedText);
//Here I get right plain text as 
//System.out: Decrypted The quick brown fox jumps over the lazy dog.


        Cipher abc=Cipher.getInstance("AES/CBC/PKCS5Padding");
        abc.init(Cipher.ENCRYPT_MODE,key,iv);
        byte[] encryptedData=abc.doFinal(decryptedData);
        String str=Base64.encodeToString(encryptedData,Base64.DEFAULT);


        System.out.println("encrypted "+str);

//Here i want the encrypted text as
// encrypted U2FsdGVkX1+tsmZvCEFa/iGeSA0K7gvgs9KXeZKwbCDNCs2zPo+BXjvKYLrJutMK+hxTwl/hy//aQLOaD7LLIRo2I5fyeRMPnroo6k8N9uwKk=
//but i receive 
//System.out: encrypted IZ5IDQruC+Cz0pd5krBsIM0KzbM+j4FeO8pgusm60wr6HFPCX+HJpAs5oPssshGjYjl/J5Ew+//eui



    }catch (Exception e)
    {}

当我解密代码时，我得到了正确的纯文本，但是当我再次加密纯文本时，我没有像以前那样得到加密文本。请帮忙。

GenerateKeyAndIV函数代码:-

 public static byte[][] GenerateKeyAndIV(int keyLength, int ivLength, int iterations, byte[] salt, byte[] password, MessageDigest md) {

    int digestLength = md.getDigestLength();
    int requiredLength = (keyLength + ivLength + digestLength - 1) / digestLength * digestLength;
    byte[] generatedData = new byte[requiredLength];
    int generatedLength = 0;

    try {
        md.reset();

        // Repeat process until sufficient data has been generated
        while (generatedLength < keyLength + ivLength) {

            // Digest data (last digest if available, password data, salt if available)
            if (generatedLength > 0)
                md.update(generatedData, generatedLength - digestLength, digestLength);
            md.update(password);
            if (salt != null)
                md.update(salt, 0, 8);
            md.digest(generatedData, generatedLength, digestLength);

            // additional rounds
            for (int i = 1; i < iterations; i++) {
                md.update(generatedData, generatedLength, digestLength);
                md.digest(generatedData, generatedLength, digestLength);
            }

            generatedLength += digestLength;
        }

        // Copy key and IV into separate byte arrays
        byte[][] result = new byte[2][];
        result[0] = Arrays.copyOfRange(generatedData, 0, keyLength);
        if (ivLength > 0)
            result[1] = Arrays.copyOfRange(generatedData, keyLength, keyLength + ivLength);

        return result;

    } catch (DigestException e) {
        throw new RuntimeException(e);

    } finally {
        // Clean out temporary data
        Arrays.fill(generatedData, (byte)0);
    }
}

Answer 1

您的密文开头有“Salted__<8 byte salt>”，您在解密时会跳过它。如果你想创建 OpenSSL 兼容的密文，你需要在你的加密模式中加上相同的前缀。

当您在 base64 到十六进制解码器中查看您的加密代码密文时，它似乎是正确的，例如提供的那个here .但是，因为每个字符仅包含 64 位，并且字节移动了 16 个位置(不能被 3 整除)，所以它只是表明您的整个密文不正确，而它只是在前面缺少 16 个字节。