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javascript - jquery ajax 添加到mysql数据库

转载 作者:行者123 更新时间:2023-11-29 04:21:55 25 4
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我想将输入字段中的数据保存到 mysql 数据库中,所以首先我创建一个模态窗口和输入字段:

<!-- Button trigger modal -->
<button class="btn btn-success" data-toggle="modal" data-target="#myModal">
Add new</button>
<div id="output"></div>
<!-- Modal -->
<div class="modal fade" id="myModal" tabindex="-1" role="dialog" aria-labelledby="myModalLabel" aria-hidden="true">
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal" aria-hidden="true">&times;</button>
<h4 class="modal-title" id="myModalLabel">Add new row</h4>
</div>
<div class="modal-body">
......
<div class="input-group">
<span class="input-group-addon">Ime</span>
<input type="text" id="Ime" class="form-control" placeholder="Upisi ime">
</div>
</br>
<div class="input-group">
<span class="input-group-addon">Pol</span>
<input type="text" id="pol" class="form-control" placeholder="Pol (male/female)">
</div>
</br>
<div class="input-group">
<span class="input-group-addon">Godine</span>
<input type="text" id="godine" class="form-control" placeholder="Godine starosti">
</div>
</br>
<div class="input-group">
<span class="input-group-addon">Broj pojedenih krofni</span>
<input type="text" id="krofne" class="form-control" placeholder="Pojedene krofne">
</div>
</br>
</div>
<div class="modal-footer">
<button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
<button id="newData" class="btn btn-primary">Add new data</button>
</div>
</div>
<!-- /.modal-content -->
</div>
<!-- /.modal-dialog -->
</div>
<!-- /.modal -->

现在我编写 jQuery AJAX 代码来向数据库添加数据:

 <script>
//add data to database using jquery ajax
$("#newData").click(function() {
//in here we can do the ajax after validating the field isn't empty.
if($("#ime").val()!="") {
$.ajax({
url: "add.php",
type: "POST",
async: true,
data: { Name:$("#ime").val(), Gender:$("#pol").val(), Age:$("#godine").val(), Donuts_eaten:$("#krofne").val()}, //your form data to post goes here as a json object
dataType: "html",

success: function(data) {
$('#output').html(data);
drawVisualization();
},
});
} else {
//notify the user they need to enter data
}
});
</script>

最后我创建了一个 php 文件 (add.php)

<?php

$con = mysql_connect('localhost', 'gmaestro_agro', 'pass') or die('Error connecting to server');

mysql_select_db('gmaestro_agro', $con);

mysql_select_db('gmaestro_agro', $con);
$query = "INSERT INTO `stat` (`Name`, `Gender`, `Age`, `Donuts eaten`) VALUES (";
$query .= mysql_real_escape_string($_POST['Name']) . ", ";
$query .= mysql_real_escape_string($_POST['Gender']) . ", ";
$query .= mysql_real_escape_string($_POST['Age']) . ", ";
$query .= mysql_real_escape_string($_POST['Donuts_eaten']);
$query .= ")";
$result = mysql_query($query);
if($result != false) {
echo "success!";
} else {
echo "an error occured saving your data!";
}

?>

现在,当我尝试添加数据时,我只收到此错误:保存您的数据时发生错误!

这里的问题到底是什么?我整天都在寻找错误...

最佳答案

你没有引用你的字符串:

$query .= mysql_real_escape_string($_POST['Name']) . ", ";

应该是:

$query .= "'" . mysql_real_escape_string($_POST['Name']) . "', ";

(对于所有字符串值)

顺便说一句,如果你切换到 PDO 或 mysqli 和准备好的语句,它可能会让你的生活更轻松。这样你就不必转义和引用你的变量,而且 mysql_* 函数无论如何都被弃用了。

关于javascript - jquery ajax 添加到mysql数据库,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/21499192/

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