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php - 警告 : mysqli_close() expects parameter 1 to be mysqli

转载 作者:行者123 更新时间:2023-11-29 04:21:06 24 4
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我在带有 MySQL 的 WAMP 服务器上有此 PHP 代码,当我访问该站点时,此错误出现在对话框中。我该如何解决这个问题?

<?php

// Create connection
$con = mysqli_connect("localhost","userdb","userdb","apptestdb");

// Check connection
if (mysqli_connect_errno($con))
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
// This SQL statement selects ALL from the table 'Locations'
$sql = "SELECT * FROM Locations";

// Check if there are results
if ($result = mysqli_query($con, $sql))
{
// If so, then create a results array and a temporary one
// to hold the data
$resultArray = array();
$tempArray = array();

// Loop through each row in the result set
while($row = $result->fetch_object())
{
// Add each row into our results array
$tempArray = $row;
array_push($resultArray, $tempArray);
}

// Finally, encode the array to JSON and output the results
echo json_encode($resultArray);
}

// Close connections
mysqli_close($result);
mysqli_close($con);
?>

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