PHP Time Since 函数错误

Question

我正在编写一个 time since 函数来返回自给定 mysql 日期时间以来的时间。当从当前时间()中获取 $oldtime 时，当我需要一个正整数时它返回一个负整数。我以前用其他语言编写过类似的功能，但我对这个问题视而不见，所以任何帮助将不胜感激。

function timeSince($time){
        $today = date("Y");
        $oldtime = strtotime($time);
        $time = time() - $oldtime;
        $tokens = array (
            3600 => 'h',
            60 => 'm',
            1 => 's'
        );

        if($time >= 86400){
        }
    }

echo timeSince('2016-02-25 14:35:00');

Answer 1

如果使用 PHP 的 DateTime 和 DateInterval 类及其方法，会方便得多:

function timeSince($datetime) {
    $now        = strtotime("now");
    $then       = strtotime($datetime);
    $dt_now     = new DateTime("@" . $now);
    $dt_then    = new DateTime("@" . $then);

    //DateTime's diff method returns a DateInterval object which got a format method:
    return $dt_now->diff($dt_then)->format('%a days, %h hours, %i minutes and %s seconds');
}

一些测试用例:

//my local date & time is around "2016-02-25 19:49:00" when testing
echo '<pre>';

echo timeSince('2016-02-25 19:30:00');
//0 days, 0 hours, 19 minutes and 11 seconds
echo PHP_EOL;

echo timeSince('2013-11-02 15:43:12'); 
//845 days, 4 hours, 4 minutes and 3 seconds
echo PHP_EOL;

echo timeSince('2017-01-31 00:22:45'); 
//340 days, 4 hours, 35 minutes and 30 seconds
echo PHP_EOL;

echo timeSince('1950-05-14 07:10:05');
//24028 days, 12 hours, 37 minutes and 10 seconds
echo PHP_EOL;

代码部分基于此答案:https://stackoverflow.com/a/19680778/3391783