php - 第二个 MySQL 查询不起作用

Question

检查这段代码:

            $select = mysql_query("SELECT * FROM nieuws ORDER BY id DESC LIMIT 1");
            while($row = mysql_fetch_assoc($select)) {
            $datum = $row['time'];
            $titel = $row['title'];
            $bericht = $row['message'];
            ?>
            <div class="entry">

                <span class="blue date"><?php echo "$datum"; ?></span>
                <h3><?php echo "$titel"; ?></h3>
                <p><?php echo "$bericht"; ?></p> <br />
            </div><!-- end of entry --> <?php } ?>
            <?php 
            $select2 = mysql_query("SELECT * FROM nieuws ORDER BY id DESC LIMI 1, 1");
            while($row2 = mysql_fetch_assoc($select2)) {
                $datum = $row2['time'];
                $titel = $row2['title'];
                $bericht = $row2['message'];
                ?>
            <div class="entry">
                <span class="green date"><?php echo "$datum"; ?> </span>
                <h3><?php echo "$titel"; ?></h3>
                <p><?php echo "$bericht"; ?></p>
            </div> <!-- end of entry --> <?php } ?>
        </div><!-- end of news --> 

第一条新闻正确显示，到第二个我得到这个错误:

警告:mysql_fetch_assoc():提供的参数不是有效的 MySQL 结果资源

有什么问题？

Answer 1

SELECT * FROM nieuws ORDER BY id DESC LIMI 1, 1

应该是

SELECT * FROM nieuws ORDER BY id DESC LIMIT 1, 1