ios - 将图像显示为弹出窗口

Question

我想在 UIPopoverArrowDirectionLeft 上显示图像。如何在单击按钮时将图像显示为弹出窗口？

Answer 1

我假设您的意思是弹出屏幕将打开，其中包含图像。这是如何做到的，只需以编程方式将图像添加到弹出 View 中，或者更好的是，直接在界面生成器中将图像添加到 MyPopOverView XIB

- (IBAction)showPopover:(id)sender
{
    if(![popoverController isPopoverVisible]) {
    myPopOver = [[MyPopOverView alloc] initWithNibName:@"MyPopOverView" bundle:nil];
    popoverController = [[UIPopoverController alloc] initWithContentViewController:myPopOver] ;

     // THE IMAGE
    UIImageView *icon = [[UIImageView alloc] initWithImage:[UIImage   imageNamed:@"popoverImage.png"]];

    [popoverController addsubview:icon];

    [popoverController setPopoverContentSize:CGSizeMake(350.0f, 500.0f)];
    [popoverController presentPopoverFromBarButtonItem:sender permittedArrowDirections:UIPopoverArrowDirectionAny animated:YES];

    } else {
        [popoverController dismissPopoverAnimated:YES];
    }
}