php - 如何使用 Laravel 构建 MySQL 查询

Question

我有一个这样的 Laravel 查询但是我得到了这样的错误

Undefined variable: keyword

$bookings = DB::table('bookings')
                    ->leftJoin('users', 'bookings.manager_id', '=', 'users.id')
                    ->leftJoin('projects', 'bookings.pr_project_id', '=', 'projects.id')
                    ->leftJoin('resources', 'bookings.pr_resource_id', '=', 'resources.id')
                    ->Where('unavailable','=','0')
                    ->orWhere(function ($query) {
                        $query->Where('users.name', 'LIKE', "%$keyword%")
                            ->Where('projects.project_name', 'LIKE', "%$keyword%")
                           ->Where('resources.r_name', 'LIKE', "%$keyword%");
                    })
                    ->orderBy('bookings.pr_working_date', 'desc')
                    ->paginate($perPage);

下面查询如何在Laravel中转换

   select * from bookings left join users on bookings.manager_id=users.id left join projects on bookings.pr_project_id=projects.id left join resources on bookings.pr_resource_id=resources.id where unavailable='0' AND (users.name like '%One Web Series%' or projects.project_name like '%One Web Series%' or resources.r_name like '%One Web Series%')

Answer 1

您需要add the use()像这样将变量传递到闭包范围:

function ($query) use($keyword) {