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mysql - 无法为 3 表 INNER JOIN (MySQL) 找出有效的 SQL - "customers also bought"功能

转载 作者:行者123 更新时间:2023-11-29 03:45:53 24 4
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我正在尝试向我的网站添加典型的“购买了‘x’的客户也购买了‘y’”的功能。这是表结构:

Table: qb_invoice
+--------------------------------+------------------+------+-----+-------------------+----------------+
| Field | Type | Null | Key | Default | Extra |
+--------------------------------+------------------+------+-----+-------------------+----------------+
| qbsql_id | int(10) unsigned | NO | PRI | NULL | auto_increment |
| TxnID | varchar(40) | YES | MUL | NULL | |
| Customer_ListID | varchar(40) | YES | MUL | NULL | |
| Customer_FullName | varchar(255) | YES | | NULL | |
+--------------------------------+------------------+------+-----+-------------------+----------------+

Table: qb_invoice_invoiceline
+-------------------------+------------------+------+-----+-------------------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-------------------------+------------------+------+-----+-------------------+----------------+
| qbsql_id | int(10) unsigned | NO | PRI | NULL | auto_increment |
| Invoice_TxnID | varchar(40) | YES | MUL | NULL | |
| Item_ListID | varchar(40) | YES | MUL | NULL | |
| Item_FullName | varchar(255) | YES | | NULL | |
+-------------------------+------------------+------+-----+-------------------+----------------+

Table: qb_customer
+-------------------------------------+------------------+------+-----+-------------------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-------------------------------------+------------------+------+-----+-------------------+----------------+
| qbsql_id | int(10) unsigned | NO | PRI | NULL | auto_increment |
| ListID | varchar(40) | YES | MUL | NULL | |
| Name | varchar(41) | YES | MUL | NULL | |
+-------------------------------------+------------------+------+-----+-------------------+----------------+

给定一个 Item_ListID 我想要一个快速、高效的查询来返回 Item_ListID 的列表以及订购每个项目的客户数量的 COUNT在列表中,所有客户都具有最初提供的 Item_ListID

现在我有以下可用的 SQL,但速度很慢:

SELECT qb_invoice_invoiceline.Item_FullName, count(*) as 'nummy'
FROM qb_invoice_invoiceline
WHERE qb_invoice_invoiceline.Invoice_TxnID =
ANY (SELECT qb_invoice.TxnID
FROM qb_invoice
INNER JOIN qb_customer ON qb_invoice.Customer_ListID = qb_customer.ListID
INNER JOIN qb_invoice_invoiceline ON qb_invoice.TxnID = qb_invoice_invoiceline.Invoice_TxnID
WHERE qb_invoice_invoiceline.Item_ListID = '1360000-57')
GROUP BY qb_invoice_invoiceline.Item_ListID
ORDER BY nummy DESC

感谢您的帮助!

这是“解释”输出:

+----+--------------------+------------------------+-------+---------------------------+-------------+---------+-----------------------------------------+-------+----------------------------------------------+
| id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra |
+----+--------------------+------------------------+-------+---------------------------+-------------+---------+-----------------------------------------+-------+----------------------------------------------+
| 1 | PRIMARY | qb_invoice_invoiceline | index | NULL | Item_ListID | 123 | NULL | 19690 | Using where; Using temporary; Using filesort |
| 2 | DEPENDENT SUBQUERY | qb_invoice_invoiceline | ref | Invoice_TxnID,Item_ListID | Item_ListID | 123 | const | 8 | Using where |
| 2 | DEPENDENT SUBQUERY | qb_invoice | ref | Customer_ListID,TxnID | TxnID | 123 | func | 206 | Using where |
| 2 | DEPENDENT SUBQUERY | qb_customer | ref | ListID | ListID | 123 | devdb.qb_invoice.Customer_ListID | 18 | Using where; Using index |
+----+--------------------+------------------------+-------+---------------------------+-------------+---------+-----------------------------------------+-------+----------------------------------------------+

最佳答案

如果您要加入的 varchar 字段上没有可用索引,您的查询可能会很慢。您能否详细说明这些表中存在的索引?

我认为查询将受益于 qb_invoice.TxnID 和 qb_customer.ListID 以及 qb_invoice_invoiceline.Item_ListID 上的索引。

关于mysql - 无法为 3 表 INNER JOIN (MySQL) 找出有效的 SQL - "customers also bought"功能,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/5535126/

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