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java - JTable 根据不在表中的属性对行进行排序

转载 作者:行者123 更新时间:2023-11-29 03:40:47 24 4
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我写了这个简单的排序函数:

public void applyFilter(String filter, int col)
{
if(filter.length() == 0)
sorter.setRowFilter(null);

RowFilter<Object, Object> rf = null;
try
{
rf = RowFilter.regexFilter(filter, col);
}
catch (java.util.regex.PatternSyntaxException e)
{
return;
}

sorter.setRowFilter(rf);
refreshTable();
}

但后来我意识到我想根据我没有向 View 显示的 ID 过滤表(因此它没有它的列)。 java过滤器是基于列的,但是如何根据其他没有显示的属性来过滤表呢?我可以轻松地获取由该行表示的基础对象并获取 ID,但是我该如何根据它进行过滤?

最佳答案

这在很大程度上取决于您的数据建模方式,但基本上您可以编写自己的过滤器...

这是我在示例中使用的过滤器实现...

    public class IDFilter extends RowFilter<MyModel, Integer> {

private int id;

public IDFilter(int id) {
this.id = id;
}

public boolean include(RowFilter.Entry<? extends MyModel, ? extends Integer> entry) {
MyModel personModel = entry.getModel();
RowValue value = personModel.getValueAt(entry.getIdentifier());
if (value.getId() == id) {
return true;
}
return false;
}

}

这是它运行的一个例子......

public class TestTableFilter {

public static void main(String[] args) {
new TestTableFilter();
}

public TestTableFilter() {
EventQueue.invokeLater(new Runnable() {
@Override
public void run() {
try {
UIManager.setLookAndFeel(UIManager.getSystemLookAndFeelClassName());
} catch (ClassNotFoundException ex) {
} catch (InstantiationException ex) {
} catch (IllegalAccessException ex) {
} catch (UnsupportedLookAndFeelException ex) {
}

JFrame frame = new JFrame("Test");
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
frame.setLayout(new BorderLayout());
frame.add(new FilterPane());
frame.pack();
frame.setLocationRelativeTo(null);
frame.setVisible(true);
}

});
}

public class FilterPane extends JPanel {

private JTable table;
private int filter;
private TableRowSorter<MyModel> sorter;

public FilterPane() {
setLayout(new BorderLayout());
MyModel model = new MyModel();
sorter = new TableRowSorter<MyModel>(model);
table = new JTable(model);
table.setRowSorter(sorter);
add(new JScrollPane(table));

JButton filterButton = new JButton("Filter");
filterButton.addActionListener(new ActionListener() {
@Override
public void actionPerformed(ActionEvent e) {
filter++;
System.out.println(filter);
RowFilter<MyModel, Integer> rowFilter = null;
switch (filter) {
case 1:
rowFilter = new IDFilter(0);
break;
case 2:
rowFilter = new IDFilter(1);
break;
default:
filter = 0;
}
sorter.setRowFilter(rowFilter);
}
});
add(filterButton, BorderLayout.SOUTH);
}

}

public class MyModel extends AbstractTableModel {

private List<RowValue> values;

public MyModel() {
values = new ArrayList<>(25);
for (int index = 0; index < 10; index++) {
values.add(new RowValue(index % 2, Character.toString((char) (65 + index)), index));
}
}

@Override
public int getRowCount() {
return values.size();
}

@Override
public int getColumnCount() {
return 2;
}

@Override
public Object getValueAt(int rowIndex, int columnIndex) {
RowValue row = values.get(rowIndex);
Object value = null;
switch (columnIndex) {
case 0:
value = row.getName();
break;
case 1:
value = row.getValue();
break;
}
return value;
}

public RowValue getValueAt(int row) {
return values.get(row);
}

}

public class RowValue {

private int id;
private String name;
private int value;

public RowValue(int id, String name, int value) {
this.id = id;
this.name = name;
this.value = value;
}

public int getId() {
return id;
}

public String getName() {
return name;
}

public int getValue() {
return value;
}

}

public class IDFilter extends RowFilter<MyModel, Integer> {

private int id;

public IDFilter(int id) {
this.id = id;
}

public boolean include(RowFilter.Entry<? extends MyModel, ? extends Integer> entry) {
MyModel personModel = entry.getModel();
RowValue value = personModel.getValueAt(entry.getIdentifier());
if (value.getId() == id) {
return true;
}
return false;
}

}

}

关于java - JTable 根据不在表中的属性对行进行排序,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/13255282/

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