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iphone - UITextField 和 NSURL URLWithString

转载 作者:行者123 更新时间:2023-11-29 03:38:26 26 4
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我在 iOS 中构建了一个翻译应用程序。该应用程序使用 Yandex 翻译 api。我遵循了本教程:http://www.raywenderlich.com/5492/working-with-json-in-ios-5我的 ViewController.m 看起来像这样(我拿出了我的 api key ):

#define kBgQueue dispatch_get_global_queue(DISPATCH_QUEUE_PRIORITY_DEFAULT, 0) //1

#import "ViewController.h"

@end
@interface NSDictionary(JSONCategories)
+(NSDictionary*)dictionaryWithContentsOfJSONURLString:(NSString*)urlAddress;
-(NSData*)toJSON;
@end

@implementation NSDictionary(JSONCategories)
+(NSDictionary*)dictionaryWithContentsOfJSONURLString:(NSString*)urlAddress
{
NSData* data = [NSData dataWithContentsOfURL: [NSURL URLWithString: urlAddress] ];
__autoreleasing NSError* error = nil;
id result = [NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&error];
if (error != nil) return nil;
return result;
}

-(NSData*)toJSON
{
NSError* error = nil;
id result = [NSJSONSerialization dataWithJSONObject:self options:kNilOptions error:&error];
if (error != nil) return nil;
return result;
}
@end

@implementation ViewController

- (void)viewDidLoad
{
[super viewDidLoad];

dispatch_async(kBgQueue, ^{
// NSData* data = [[NSData dataWithContentsOfURL: TranslateText] ];
NSData*data = [NSURL URLWithString: [NSString stringWithFormat: @"https://translate.yandex.net/api/v1.5/tr.json/translate?key=apikeys&lang=en-es&text=%@", textfield.text]];
[self performSelectorOnMainThread:@selector(fetchedData:) withObject:data waitUntilDone:YES];
});
}

- (void)fetchedData:(NSData *)responseData {
//parse out the json data
NSError* error;
NSDictionary* json = [NSJSONSerialization JSONObjectWithData:responseData //1
options:kNilOptions
error:&error];
NSArray* TranslatedText = [json objectForKey:@"text"]; //2

NSLog(@"Text that was translated: %@", TranslatedText); //3

// 1) Get the latest loan
//NSDictionary* ttext = [TranslatedText objectAtIndex:0];
NSString* ttext = [TranslatedText objectAtIndex:0];


// 3) Set the label appropriately
humanReadble.text = [NSString stringWithFormat:@"%@",
//[ttext objectForKey:@"name"],
ttext];

}

@end`

当我运行应用程序时,我在这行代码上收到错误Thread 1: signal SIGABRT: 返回 UIApplicationMain(argc, argv, nil, NSStringFromClass([AppDelegate class]));我该怎么办?

最佳答案

您的代码中的错误是那里使用了冒号。你应该让这条线...

[NSURL URLWithString: [NSString stringWithFormat: @"https://translate.yandex.net/api/v1.5/tr.json/translate?apikeyes&text=%@", textfield.text];

此外,我不知道您为什么要执行#define。在处理按钮被按下的方法中获取信息。

NSURL * translateURL = [NSURL URLWithString: [NSString stringWithFormat: @"https://translate.yandex.net/api/v1.5/tr.json/translate?apikeyes&text=%@", textfield.text];

关于iphone - UITextField 和 NSURL URLWithString,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/18804558/

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