mysql - 主键列不允许空值

Question

我有一个关于主键或复合键的问题。我创建了一个表，其中只有两个属性并且都是主键。

主键名称是item_ID̀ 和SName`

这两个是另一个主键(到另外两个表)的外键，其中:item_ID --> ID 和 SName --> SkillName

ITEM ID      SName1        Basic weapons2   3   4        Heavy weapon5        Exotic Weapons6        Heavy weapon7        Power weapon

and the outcome is this:

The ID nr 2 and 3 does not need a skillname requirement. For that reason I have implemented like this (since a primary key is not allowed a null):

INSERT INTO Requierments (item_ID, SName) VALUES ( 
01, 'Basic weapons');

INSERT INTO Requierments (item_ID, SName) VALUES ( 
02, null);

INSERT INTO Requierments (item_ID, SName) VALUES ( 
03, null);

INSERT INTO Requierments (item_ID, SName) VALUES ( 
04, 'Heavy weapon');

INSERT INTO Requierments (item_ID, SName) VALUES ( 
05, 'Exotic Weapons');

INSERT INTO Requierments (item_ID, SName) VALUES ( 
06, 'Heavy weapon');

INSERT INTO Requierments (item_ID, SName) VALUES ( 
07, 'Power weapon');

这样做正确吗？还是有另一种编码方式，使 ID 不需要特定的 SName？

---

这是 3 个表的代码:

CREATE TABLE `talents` (
  `SkillName` varchar(30) NOT NULL DEFAULT '',
  `Bonus` varchar(30) DEFAULT NULL,
  `Description` varchar(70) DEFAULT NULL,
  `R_Str` int(11) DEFAULT NULL,
  `R_WS` int(11) DEFAULT NULL,
  `R_BS` int(11) DEFAULT NULL,
  `R_Fel` int(11) DEFAULT NULL,
  `R_Per` int(11) DEFAULT NULL,
  `R_Int` int(11) DEFAULT NULL,
  `R_Agi` int(11) DEFAULT NULL,
  `R_WP` int(11) DEFAULT NULL,
  `Talent_requiert` varchar(30) DEFAULT NULL,
  PRIMARY KEY (`SkillName`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;

CREATE TABLE `requierments` (
  `item_ID` int(11) NOT NULL DEFAULT '0',
  `SName` varchar(30) NOT NULL DEFAULT '',
  PRIMARY KEY (`item_ID`,`SName`),
  CONSTRAINT `requierments_ibfk_1` FOREIGN KEY (`item_ID`) REFERENCES `item` (`ID`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;


CREATE TABLE `item` (
  `ID` int(11) NOT NULL DEFAULT '0',
  `Name_` varchar(30) DEFAULT NULL,
  `Weight` int(11) DEFAULT NULL,
  `Value_` int(11) DEFAULT NULL,
  `Availability` varchar(30) DEFAULT NULL,
  PRIMARY KEY (`ID`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;

这个想法是在需求表item_ID ---> ID在item表和SName ---> SkillName在talents中。出于某种原因，我能够创建从 item_ID 到 ID 的外键，但不能从 SName 到 SkillName:

我添加到这些表中的值如下(OBS，在表要求中我将 ID 2 和 3 设置为“”，因为不需要任何才能来选择它。但我不确定我是否可以使用该方法吗？

INSERT INTO Talents ( SkillName, Bonus, Description, R_Str, R_WS, R_BS, R_Fel, R_Per, R_Int, R_Agi, R_WP, Talent_requiert) VALUES (
 'ambidextrous', 0, 'use either hand equally well', 0, 0, 0, 0, 0, 0, 30, 0, null);

INSERT INTO Talents ( SkillName, Bonus, Description, R_Str, R_WS, R_BS, R_Fel, R_Per, R_Int, R_Agi, R_WP, Talent_requiert) VALUES (
 'Frenzy', 0, 'enter psychotic rage to gain combat bonus', 0, 0, 0, 0, 0, 0, 0, 0, null);

INSERT INTO Talents ( SkillName, Bonus, Description, R_Str, R_WS, R_BS, R_Fel, R_Per, R_Int, R_Agi, R_WP, Talent_requiert) VALUES (
 'battle rage', 0, 'parry while frenzied', 0, 0, 0, 0, 0, 0, 0, 0, 'Frenzy');

INSERT INTO Talents ( SkillName, Bonus, Description, R_Str, R_WS, R_BS, R_Fel, R_Per, R_Int, R_Agi, R_WP, Talent_requiert) VALUES (
 'Exotic Weapons', 0, 'Player is able to use exotic weapons', 0, 0, 0, 0, 0, 0, 0, 0, 'Basic weapons');

INSERT INTO Talents ( SkillName, Bonus, Description, R_Str, R_WS, R_BS, R_Fel, R_Per, R_Int, R_Agi, R_WP, Talent_requiert) VALUES (
 'Basic weapons', 0, 'Player is able to use Basic weapons', 0, 0, 0, 0, 0, 0, 0, 0, null);

INSERT INTO Talents ( SkillName, Bonus, Description, R_Str, R_WS, R_BS, R_Fel, R_Per, R_Int, R_Agi, R_WP, Talent_requiert) VALUES (
 'Heavy weapon', 0, 'Player is able to use heavy weapons', 30, 0, 0, 0, 0, 0, 0, 0, null);

INSERT INTO Talents ( SkillName, Bonus, Description, R_Str, R_WS, R_BS, R_Fel, R_Per, R_Int, R_Agi, R_WP, Talent_requiert) VALUES (
 'Power weapon', 0, 'Player is able to use power weapons ', 40, 30, 0, 0, 0, 0, 0, 0, null);



INSERT INTO Item ( ID, Name_, Weight, Value_, Availability) VALUES (
01, 'Las Carbine', 3, 75, 'Common' );

INSERT INTO Item ( ID, Name_, Weight, Value_, Availability) VALUES (
02, 'Laspistol', 1, 50, 'Common' );

INSERT INTO Item ( ID, Name_, Weight, Value_, Availability) VALUES (
03, 'Shotgun', 5, 60, 'average' );

INSERT INTO Item ( ID, Name_, Weight, Value_, Availability) VALUES (
04, 'Heavy Bolter', 40, 2000, 'Very Rare' );

INSERT INTO Item ( ID, Name_, Weight, Value_, Availability) VALUES (
05, 'Needle pistol', 2, 1250, 'Very Rare' );

INSERT INTO Item ( ID, Name_, Weight, Value_, Availability) VALUES (
06, 'Chainsword', 6, 275, 'Rare' );

INSERT INTO Item ( ID, Name_, Weight, Value_, Availability) VALUES (
07, 'Power Sword', 4, 2500, 'Very Rare' );


INSERT INTO Requierments (item_ID, SName) VALUES ( 
01, 'Basic weapons');

INSERT INTO Requierments (item_ID, SName) VALUES ( 
02, '');

INSERT INTO Requierments (item_ID, SName) VALUES ( 
03, '');

INSERT INTO Requierments (item_ID, SName) VALUES ( 
04, 'Heavy weapon');

INSERT INTO Requierments (item_ID, SName) VALUES ( 
05, 'Exotic Weapons');

INSERT INTO Requierments (item_ID, SName) VALUES ( 
06, 'Heavy weapon');

INSERT INTO Requierments (item_ID, SName) VALUES ( 
07, 'Power weapon');

Answer 1

您正在尝试处理 Item 没有Requirement 的情况。换句话说，这样的 Item 与 Talent 没有关系:只是不要在 Requirements 中插入任何内容这个项目!