java - Spring MVC Controller 没有返回正确的 View

Question

当用户请求管理人员/用户页面时，如果 cookie 中有用户名，我会在 cookie 中存储一个用户名 (jeff)，我想向用户显示管理人员/用户的详细信息。我使用 ajax 请求 来获取详细信息。

ajax 请求转到 Controller 并获取数据，但是当我将 view 返回给用户时 Object 为 null。因此没有数据绑定(bind)到对象。然后 View 是空的。我想将具有官员/用户数据的对象返回给用户。

下面是我的代码和 Firebug 请求的屏幕截图。请告诉我哪里出错了。

来自 View 的 Ajax 请求

<script type="text/javascript"> 
  function getCookie(name) {
    var regexp = new RegExp("(?:^" + name + "|;\s*"+ name + ")=(.*?)(?:;|$)", "g");
    var result = regexp.exec(document.cookie);
    return (result === null) ? null : result[1];
  }

  var userName = getCookie("userName");
  console.log(getCookie("userName"));

  if(userName != null & userName != 'Guest'){
     alert('Redirecting to get officer');

    $.ajax({
            type:'POST',
        url:'getOfficer/'+ userName + '.htm',
        contentType: "application/json",
        async: false,
        cache: false, 
        data:userName                   
        });     
    }

Controller

 @RequestMapping(value="getOfficer/{userName}.htm", method = RequestMethod.POST)
 public ModelAndView getOfficer(@PathVariable String userName,@ModelAttribute Officers officer, 
BindingResult result,ModelMap m,Model model,HttpServletRequest request,  
HttpServletResponse response) {

 logger.info("In get Officer by userName");
 try{
    model.addAttribute("officers",officerManager.getOfficer(userName));
 }catch(Exception e){
    logger.error("Exception In Officer Controller getOfficer/{userName} " + e.getMessage());
    request.setAttribute("error",e.getMessage());
 }

 logger.info("about to return new officer_registration");
 logger.info("Officer Badge Number is "+officer.getBadgeNo());
 logger.info("Officer First and last name is "+officer.getfName() + " - " + officer.getlName());

 return new ModelAndView("officer_registration");    

}

带有 Logger.info 消息的错误日志

我注意到这一行表明模型为空。为什么？

758511 [http-bio-8084-exec-9] DEBUG org.springframework.web.servlet.mvc.method.annotation.ServletInvocableHandlerMethod  - Method [postOfficer] returned [ModelAndView: reference to view with name 'officer_registration'; model is null


758470 [http-bio-8084-exec-9] INFO  com.crimetrack.web.OfficerController  - In get Officer by userName
758470 [http-bio-8084-exec-9] INFO  com.crimetrack.jdbc.JdbcOfficersDAO  - Getting Officer in getOfficer(String userName)
758506 [http-bio-8084-exec-9] DEBUG org.springframework.jdbc.core.JdbcTemplate  - Executing prepared SQL query
758506 [http-bio-8084-exec-9] DEBUG org.springframework.jdbc.core.JdbcTemplate  - Executing prepared SQL statement [SELECT * FROM crimetrack.tblofficers WHERE userName = ?]
758506 [http-bio-8084-exec-9] DEBUG org.springframework.jdbc.datasource.DataSourceUtils  - Fetching JDBC Connection from DataSource
758508 [http-bio-8084-exec-9] DEBUG org.springframework.jdbc.core.StatementCreatorUtils  - Setting SQL statement parameter value: column index 1, parameter value [jeff], value class [java.lang.String], SQL type unknown
758510 [http-bio-8084-exec-9] DEBUG org.springframework.jdbc.datasource.DataSourceUtils  - Returning JDBC Connection to DataSource
758511 [http-bio-8084-exec-9] INFO  com.crimetrack.web.OfficerController  - about to return new officer_registration
758511 [http-bio-8084-exec-9] INFO  com.crimetrack.web.OfficerController  - Officer Badge Number is null
758511 [http-bio-8084-exec-9] INFO  com.crimetrack.web.OfficerController  - Officer First and last name is null - null
758511 [http-bio-8084-exec-9] DEBUG org.springframework.web.servlet.mvc.method.annotation.ServletInvocableHandlerMethod  - Method [postOfficer] returned [ModelAndView: reference to view with name 'officer_registration'; model is null]
758511 [http-bio-8084-exec-9] DEBUG org.springframework.web.method.support.InvocableHandlerMethod  - Invoking [initBinder] method with arguments [org.springframework.web.servlet.mvc.method.annotation.ExtendedServletRequestDataBinder@b836456]
758512 [http-bio-8084-exec-9] DEBUG org.springframework.web.method.support.InvocableHandlerMethod  - Method [initBinder] returned [null]
758512 [http-bio-8084-exec-9] DEBUG org.springframework.web.servlet.DispatcherServlet  - Rendering view [org.springframework.web.servlet.view.JstlView: name 'officer_registration'; URL [/WEB-INF/jsp/officer_registration.jsp]] in DispatcherServlet with name 'crimetrack'
758512 [http-bio-8084-exec-9] DEBUG org.springframework.web.servlet.view.JstlView  - Rendering view with name 'officer_registration' with model {officers=com.crimetrack.business.Officers@5f305001, org.springframework.validation.BindingResult.officers=org.springframework.validation.BeanPropertyBindingResult: 0 errors} and static attributes {}
758512 [http-bio-8084-exec-9] DEBUG org.springframework.web.servlet.view.JstlView  - Added model object 'officers' of type [com.crimetrack.business.Officers] to request in view with name 'officer_registration'
758512 [http-bio-8084-exec-9] DEBUG org.springframework.web.servlet.view.JstlView  - Added model object 'userName' of type [java.lang.String] to request in view with name 'officer_registration'
758512 [http-bio-8084-exec-9] DEBUG org.springframework.web.servlet.view.JstlView  - Added model object 'org.springframework.validation.BindingResult.officers' of type [org.springframework.validation.BeanPropertyBindingResult] to request in view with name 'officer_registration'
758513 [http-bio-8084-exec-9] DEBUG org.springframework.beans.factory.support.DefaultListableBeanFactory  - No bean named 'requestDataValueProcessor' found in org.springframework.beans.factory.support.DefaultListableBeanFactory@726b5b3c: defining beans [citizenManager,validateCitizenManager,citizenDao,citizenTypeManager,citizenTypeDao,markerManager,markerDao,crimeHotSpotManager,crimeHotSpotDao,crimeManager,crimeRegistrationValidation,crimeDao,colorManager,colorDao,monitoringTypeManager,monitoringTypeDao,monitoringManager,monitoringDao,ethnicityManager,ethnicityDao,crimeLevelManager,crimeLevelDao,crimeTypeManager,crimeTypeDao,statusManager,statusDao,crimeCategoryManager,crimeCategoryDao,maritalStatusManager,maritalStatusDao,occupationManager,occupationDao,officerManager,countryManager,countryDao,authenticationManager,loginDao,divisionManager,divisionDao,positionManager,positionDao,genderManager,genderDao,officerRegistrationValidation,validateUserManager,officerDao,dataSource,propertyConfigurer,transactionManager]; root of factory hierarchy
758513 [http-bio-8084-exec-9] DEBUG org.springframework.web.servlet.view.JstlView  - Forwarding to resource [/WEB-INF/jsp/officer_registration.jsp] in InternalResourceView 'officer_registration'
758514 [http-bio-8084-exec-9] DEBUG org.springframework.beans.factory.support.DefaultListableBeanFactory  - No bean named 'requestDataValueProcessor' found in org.springframework.beans.factory.support.DefaultListableBeanFactory@726b5b3c: defining beans [citizenManager,validateCitizenManager,citizenDao,citizenTypeManager,citizenTypeDao,markerManager,markerDao,crimeHotSpotManager,crimeHotSpotDao,crimeManager,crimeRegistrationValidation,crimeDao,colorManager,colorDao,monitoringTypeManager,monitoringTypeDao,monitoringManager,monitoringDao,ethnicityManager,ethnicityDao,crimeLevelManager,crimeLevelDao,crimeTypeManager,crimeTypeDao,statusManager,statusDao,crimeCategoryManager,crimeCategoryDao,maritalStatusManager,maritalStatusDao,occupationManager,occupationDao,officerManager,countryManager,countryDao,authenticationManager,loginDao,divisionManager,divisionDao,positionManager,positionDao,genderManager,genderDao,officerRegistrationValidation,validateUserManager,officerDao,dataSource,propertyConfigurer,transactionManager]; root of factory hierarchy
758528 [http-bio-8084-exec-9] DEBUG org.springframework.web.servlet.DispatcherServlet  - Cleared thread-bound request context: org.apache.catalina.connector.RequestFacade@51dd475f
758528 [http-bio-8084-exec-9] DEBUG org.springframework.web.servlet.DispatcherServlet  - Successfully completed request

屏幕截图

用户名是Jeff

这是来自 firebug，它显示 POST jeff.htm 正在返回数据。我认为返回的 View 不正确。

Officer_Registration.jsp

</head>
<body>
  <form:form id="officerRegistration" name="officerRegistration" method="post" modelAttribute="officers" action="officer_registration.htm">
  <ol>
  <li>
    <label>Badge No</label>
    <form:input path="badgeNo" id="badgeNo" title="Enter a Valid Badge Number"
      readonly="${badgeNoStatus}" class="formData" />
    <form:errors path="badgeNo" class="errors" />
    <label id="badgeNoErr"></label>
  </li>
  <li>
    <form:label for="userName" path="userName">User Name</form:label>
    <form:input path="userName" id="userName" title="Choose A Unique UserName"
      readonly="${userNameStatus}" class="formData" />
    <form:errors path="userName" class="errors" />
    <label id="userNameErr"></label>
  </li>
  <li>
    <label>Password</label>
    <form:password path="password" id="password" class="formData" />
    <form:errors path="password" class="errors" />
  </li>
  <li>
    <label>Re-Enter Password</label>
    <form:password path="password2" id="password2"
      class="formData" />
    <form:errors path="password2" class="errors" />
  </li>
  <li>
    <label>e-Mail Address</label>
    <form:input path="emailAdd" id="emailAdd" title="Enter eMail Address"
      class="formData" />
    <form:errors path="emailAdd" class="errors" />
  </li>
  <li>
    <label>First Name</label>
    <form:input path="fName" id="fName" title="Your First Name"
      class="formData" />
    <form:errors path="fName" class="errors" />
  </li>
  <li>
    <label>Last Name</label>
    <form:input path="lName" id="lName" title="Your Last Name"
      class="formData" />
    <form:errors path="lName" class="errors" />
  </li>
  <li>

Answer 1

查看您问题中的最后一张图片，我可以看出您正在使用 jQuery，并且看起来您正在收到包含 HTML 的响应。我假设您正在使用 jQuery 发出 ajax 请求(例如使用 $.ajax 或 $.get)。假设您正在使用 jQuery's ajax function .你的 js 代码看起来像这样:

function getOfficerInfo(officerUserName) {
    var officerUrl = "/crimeTrack/getOffice/" + officerUserName + ".htm"
    $.ajax({
        url: officerUrl,
        type: "GET"
    });
}

这会向服务器发送 GET 请求，服务器会返回响应中显示的 html，您在图像中查看。但是，此代码不处理响应。为此，您需要在传递给 $.ajax 函数的 javascript 对象中添加一个成功字段(或者您可以使用 $.ajax 函数返回一个 promise，但让我们坚持最基本的 :))。

function getOfficerInfo(officerUserName) {
    var officerUrl = "/crimeTrack/getOffice/" + officerUserName + ".htm"
    $.ajax({
        url: officerUrl,
        type: "GET",
        success: function(data) {
            $("#form-container").html(data);
        }
    });
}

当 ajax 请求成功时，success 函数将被调用，data 变量将保存响应中的数据。在这里，我假设您在页面上有一些元素，其 ID 为 form-container，其内容可以替换为您的 html 响应。

请注意，这里没有错误处理，因此您应该添加一个 error 函数来处理超时、服务器端错误等。

最后。我建议您将数据作为 JSON 传输，并只更新现有表单中的值。 Spring 非常支持使用 @ResponseBody 注释返回 JSON。