java - 每当鼠标在场景上移动时如何使节点移动(在 JavaFX 中)？

Question

我编写了一个小型 JavaFX 程序，其中只要鼠标光标在包含矩形的场景上移动，矩形节点就会移动。这是我的代码:

public class MovedObjectWhenMouseMoved extends Application{
double nodeX;
double currentMousePos;
double oldMousePos = 0.0;   
public static void main(String[] arg){
    launch(arg);
}

@Override
public void start(Stage stage) throws Exception {
    final Rectangle rect = new Rectangle(50, 50, Color.RED);
    rect.setX(20);
    rect.setY(20);

    AnchorPane anchorPane = new AnchorPane();
    anchorPane.getChildren().add(rect);
    Scene scene = new Scene(anchorPane,500,500,Color.GREEN);
    stage.setScene(scene);
    stage.show();

    scene.setOnMouseMoved(new EventHandler<MouseEvent>() {

        @Override
        public void handle(MouseEvent mouseEvent) {

            currentMousePos = mouseEvent.getX();                

            if(currentMousePos>oldMousePos){                    
                rect.setX(rect.getX()+1);  // Move right 
            }else if(currentMousePos<oldMousePos){
                rect.setX(rect.getX()-1); // Move Left
            }

            oldMousePos = currentMousePos;  
        }

    });
  }
}

但这里的问题是节点速度与鼠标速度不同。我该如何解决这个问题？如果有更好的方法，也请告诉我。

Answer 1

鼠标可以改变超过 1 个像素的位置。

为 handle 尝试此代码:

currentMousePos = mouseEvent.getX();
double dX = currentMousePosition - oldMousePos;                
rect.setX(rect.getX() + dX);
oldMousePos = currentMousePos;