ios - 自定义 TableviewCell 中的按钮不接受该操作。当我点击重试按钮时，它会抛出 exc_bad_access 信号。

Question

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
if(indexPath.section == 0){
    UITableViewCell* cell = nil;
    if (indexPath.row < kTotalScreens) {
        if ([self.tableCellsPrecreated count]>=kTotalScreens) {
            cell = [self.tableCellsPrecreated objectAtIndex:indexPath.row];
        }

    }
    return cell;
}else
{
    UITableViewCell* cell = [tableView dequeueReusableCellWithIdentifier:cellIDForHome];
    if (indexPath.row < [_subActionArray count])
    {
        if(cell == nil)
        {
        cell = [self getCellForCategoryActionForRow];
        NSLog(@"************cell %d created",indexPath.row);
        }
        GridViewController *controller = [self getControllerForCategoryActionCellAtIndex:indexPath.row
                                                                                 andCell:(TitleWithGridViewCell*)cell];
        [self reloadDataForController:controller
                      contentCategory:((CategoryAction *)[_subActionArray objectAtIndex:indexPath.row]).category
                             cellView:(TitleWithGridViewCell*)cell];
    }
    return cell;
}
}


-(UITableViewCell*)getCellForCategoryActionForRow
{
TitleWithGridViewCell* cell = [[[NSBundle mainBundle]loadNibNamed:@"TitleWithGridViewCell" owner:self options:nil]objectAtIndex:0];
CGRect frameCell = cell.contentView.bounds;
frameCell.size.height = [cell heightOfCellForSubCellofSize:CellSizeSmall viewClass:[EntityCellView class] numRows:1];
[cell setFrame:frameCell];
cell.delegate = self;
cell.accessibilityLabel =[NSString stringWithFormat:@"Category Channels Grid"];
return cell;
}

-(GridViewController*)getControllerForCategoryActionCellAtIndex :(NSInteger)index andCell:(TitleWithGridViewCell*)cell
{
GridViewController* gridController = nil;
CellViewFactory *channelCellFactory = [[CellViewFactory alloc] initWithWantedCellSize:CellSizeSmall cellViewClass:[EntityCellView class]];
ChannelsForCategoryDataFetcher *channelsForCategoryDataFetcher = [ChannelsForCategoryDataFetcher new];
PrefetchingDataSource *dataSource = [PrefetchingDataSource createWithDataFetcher:channelsForCategoryDataFetcher];
dataSource.sortBy = ProgramSortByRatingCount;
dataSource.objectsPrPage = 6;
if (cell) {
    gridController = [[GridViewController alloc] initWithGridView:[cell getGridView] gridCellFactory:channelCellFactory dataSource:dataSource];
    gridController.delegate = self;
}
return gridController;
}

上面的代码创建一个自定义的tableviewcell和该单元格的 Controller 。每个单元格都包含一个重试按钮，在网络故障的情况下。表格显示所有数据和单元格都很好。但是在点击单元格中的重试按钮时，它会显示exc_bad_access。

Answer 1

在您的自定义单元格端，

1) 使自定义单元格的 .h 文件的协议(protocol)类似于

@protocol CustomCellDelegate
@optional
- (void)tryAgainButtonTappedOnCell:(id)sender;
@end

2) 在你的.h 文件中设置delegate 并在click 方法上设置Custom Cell 的按钮

@property (nonatomic, strong) id<CustomCellDelegate> delegate;
- (IBAction)tryAgainButtonTapped:(id)sender;

3) 在你的 .m 文件中，

- (IBAction)tryAgainButtonTapped:(id)sender {
    [self.delegate tryAgainButtonTappedOnCell:self];
}

4) 将 IBAction 与按钮链接起来

5) 取消选中使用自定义单元格的自动布局

在您的 TableView 端，

1) 设置自定义单元格的委托(delegate)

@interface SomeViewController : UIViewController<UITableViewDelegate, UITableViewDataSource, CustomCellDelegate>

2) 在 - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath 中，设置单元格的委托(delegate) cell.delegate=self。

3) 根据您的需要实现新制作的委托(delegate)功能，即

- (void)tryAgainButtonTappedOnCell:(id)sender
{
//your logic
}

希望对你有帮助。

干杯