java - NetworkOnMainThreadException 有时会抛出

Question

我尝试从 POST 请求中获取响应。问题是，尽管我正在使用 AsyncTask 进行网络通信，但有时我会得到 NetworkOnMainThreadException。这意味着有时我成功获得响应，有时我得到这个异常。

这是我的 HTTP POST 请求 AsyncTask:

static class HTTPPostRequest extends AsyncTask<PostRequestParams, Void, AsyncResponse> {

    @Override
    protected AsyncResponse doInBackground(PostRequestParams... params) {
        AsyncResponse retVal = new AsyncResponse();
        HttpClient client = getHttpClient();
        UrlEncodedFormEntity formEntity = null;
        HttpPost request = new HttpPost();

        try {
            request.setURI(new URI(params[0].URL));
            formEntity = new UrlEncodedFormEntity(params[0].params);
            request.setEntity(formEntity);

            HttpResponse response = client.execute(request);
            retVal.setOutput(response);

        } catch (ClientProtocolException e) {
            retVal.setException(e);
        } catch (IOException e) {
            retVal.setException(e);
        } catch (URISyntaxException e) {
            retVal.setException(e);
        }

        return retVal;
    }

}

以及实际调用它的代码:

AsyncResponse response = new AsyncResponse(); 
    PostRequestParams postParams = new PostRequestParams();
    postParams.URL = URL + "login.php";
    postParams.params.add(new BasicNameValuePair("username", username));
    postParams.params.add(new BasicNameValuePair("password", password));

    try {
        response = new HTTPPostRequest().execute(postParams).get();
        if (response.getException() != null) {
            return "Error";
        }
        HttpResponse httpResponse = (HttpResponse) response.getOutput();
        if (httpResponse.getStatusLine().getStatusCode() != 200) {
            return "Error " + httpResponse.getStatusLine().getStatusCode();
        }

        return (String) formatResponse(new BufferedReader(new InputStreamReader(httpResponse.getEntity().getContent())));
    } catch (InterruptedException | ExecutionException | IllegalStateException | IOException e) {
        response.setException(e);
        return null;
    }

Answer 1

您应该移动处理 InputStream 的代码，例如:

 return (String) formatResponse(new BufferedReader(new InputStreamReader(httpResponse.getEntity().getContent())));

还有你的 AsyncTask。您不想在 UI 线程中处理 InputStreams。