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php - 提交表单后如何使下拉菜单值仍处于选中状态？

转载 作者：行者123 更新时间：2023-11-29 03:11:23 24 4
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当我在文本框中输入数据并提交表单时，数据仍存储在文本框中，这非常好 例如我使用 .我现在想做的是，当从下拉菜单中选择一个值并提交表单时，我希望选择的值仍显示为下拉列表中的选定值，但我无法做到这一点。有什么想法吗？

代码如下:

  <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>

<title>Exam Interface</title>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
</head>
<body>

<?php

$username="xxx";
$password="xxx";
$database="mobile_app";

mysql_connect('localhost',$username,$password);

@mysql_select_db($database) or die("Unable to select database");



$sessionid = isset ($_POST['sessionid']) ? $_POST['sessionid'] : "";
$moduleid = isset ($_POST['moduleid']) ? $_POST['moduleid'] : "";
$teacherid = isset ($_POST['teacherid']) ? $_POST['teacherid'] : "";
$studentid = isset ($_POST['studentid']) ? $_POST['studentid'] : "";
$grade = isset ($_POST['grade']) ? $_POST['grade'] : "";
$orderfield = isset ($_POST['order']) ? $_POST['order'] : "";

$sessionid = mysql_real_escape_string($sessionid);
$moduleid = mysql_real_escape_string($moduleid);
$teacherid = mysql_real_escape_string($teacherid);
$studentid = mysql_real_escape_string($studentid);
$grade = mysql_real_escape_string($grade);

?>

<p><strong>NOTE: </strong>If a search box is left blank, then the form will search for all data under that specific field</p>

<form action="exam_interface.php" method="post" name="sessionform">        <!-- This will post the form to its own page"-->
<p>Session ID: <input type="text" name="sessionid" value="<?PHP print $sessionid ; ?>" /></p>      <!-- Enter Session Id here-->
<p>Module Number: <input type="text" name="moduleid" value="<?PHP print $moduleid ; ?>" /></p>      <!-- Enter Module Id here-->
<p>Teacher Username: <input type="text" name="teacherid" value="<?PHP print $teacherid ; ?>" /></p>      <!-- Enter Teacher here-->
<p>Student Username: <input type="text" name="studentid" value="<?PHP print $studentid ; ?>" /></p>      <!-- Enter User Id here-->
<p>Grade: <input type="text" name="grade" value="<?PHP print $grade ; ?>" /></p>      <!-- Enter Grade here-->
<p>Order Results By: <select name="order" value="<?PHP print $orderfield ; ?>">
<option value="ordersessionid">Session ID</option>
<option value="ordermoduleid">Module Number</option>
<option value="orderteacherid">Teacher Username</option>
<option value="orderstudentid">Student Username</option>
<option value="ordergrade">Grade</option>
</select>
<p><input type="submit" value="Submit" name="submit" /></p>
</form>

<?php

$username="u0867587";
$password="31may90";
$database="mobile_app";

mysql_connect('localhost',$username,$password);

@mysql_select_db($database) or die("Unable to select database");



$sessionid = isset ($_POST['sessionid']) ? $_POST['sessionid'] : "";
$moduleid = isset ($_POST['moduleid']) ? $_POST['moduleid'] : "";
$teacherid = isset ($_POST['teacherid']) ? $_POST['teacherid'] : "";
$studentid = isset ($_POST['studentid']) ? $_POST['studentid'] : "";
$grade = isset ($_POST['grade']) ? $_POST['grade'] : "";
$orderfield = isset ($_POST['order']) ? $_POST['order'] : "";

$sessionid = mysql_real_escape_string($sessionid);
$moduleid = mysql_real_escape_string($moduleid);
$teacherid = mysql_real_escape_string($teacherid);
$studentid = mysql_real_escape_string($studentid);
$grade = mysql_real_escape_string($grade);

if(isset($_POST['submit'])) {

switch ($orderfield) {
    case 'ordersessionid': $orderfield = 'gr.SessionId';
    break;
    case 'ordermoduleid': $orderfield = 'm.ModuleId'; 
    break;
    case 'orderteacherid': $orderfield = 's.TeacherId';
    break;
    case 'orderstudentid': $orderfield = 'gr.StudentId'; 
    break;
    case 'ordergrade': $orderfield = 'gr.Grade';
    break;
}

$result = mysql_query("SELECT * FROM Module m INNER JOIN Session s ON m.ModuleId = s.ModuleId JOIN Grade_Report gr ON s.SessionId = gr.SessionId JOIN Student st ON gr.StudentId = st.StudentId WHERE ('$sessionid' = '' OR gr.SessionId = '$sessionid') AND ('$moduleid' = '' OR m.ModuleId = '$moduleid') AND ('$teacherid' = '' OR s.TeacherId = '$teacherid') AND ('$studentid' = '' OR gr.StudentId = '$studentid') AND ('$grade' = '' OR gr.Grade = '$grade') ORDER BY $orderfield ASC");

$num=mysql_numrows($result);

echo "<p>Your Search: <strong>Session ID:</strong> "; if (empty($sessionid))echo "'All Sessions'"; else echo "'$sessionid'";echo ", <strong>Module ID:</strong> "; if (empty($moduleid))echo "'All Modules'"; else echo "'$moduleid'";echo ", <strong>Teacher Username:</strong> "; if (empty($teacherid))echo "'All Teachers'"; else echo "'$teacherid'";echo ", <strong>Student Username:</strong> "; if (empty($studentid))echo "'All Students'"; else echo "'$studentid'";echo ", <strong>Grade:</strong> "; if (empty($grade))echo "'All Grades'"; else echo "'$grade'"; echo ", <strong>Order Results By:</strong>";if ($orderfield == 'gr.SessionId') echo " 'Session ID'"; else if ($orderfield == 'm.ModuleId') echo " 'Module Number' "; else if ($orderfield == 's.TeacherId') echo " 'Teacher Username' "; else if ($orderfield == 'gr.StudentId') echo " 'Student Username' "; else if ($orderfield == 'gr.Grade') echo " 'Grade' ";"</p>";

echo "<p>Number of Records Shown in Result of the Search: <strong>$num</strong></p>";

echo "<table border='1'>
<tr>
<th>Student Id</th>
<th>Forename</th>
<th>Session Id</th>
<th>Grade</th>
<th>Mark</th>
<th>Module</th>
<th>Teacher</th>
</tr>";

while ($row = mysql_fetch_array($result)){

 echo "<tr>";
  echo "<td>" . $row['StudentId'] . "</td>";
  echo "<td>" . $row['Forename'] . "</td>";
  echo "<td>" . $row['SessionId'] . "</td>";
  echo "<td>" . $row['Grade'] . "</td>";
  echo "<td>" . $row['Mark'] . "</td>";
  echo "<td>" . $row['ModuleName'] . "</td>";
  echo "<td>" . $row['TeacherId'] . "</td>";
  echo "</tr>";
}

echo "</table>";

}

mysql_close();


 ?>

</body>
</html>

谢谢你，任何帮助对我来说都是一个很大的帮助。

最佳答案

这是我会做的。它既不迷人也不完美，但效果非常好。如果来自表单提交的值匹配，您只需设置一个变量以将所选属性添加到您的选项标签。然后仅当该变量与该选项匹配时才输出所选属性。这可能更难，但它有效并且易于理解。

为选择本身添加一个值实际上对您没有任何作用。它必须添加到您希望自动选择的特定选项上。

<?php if($orderfield=='ordersessionid'){$session = ' selected="selected"';} ?>
<?php if($orderfield=='ordermoduleid'){$module = ' selected="selected"';} ?>
<?php if($orderfield=='orderteacherid'){$teacher = ' selected="selected"';} ?>
<?php if($orderfield=='orderstudentid'){$student = ' selected="selected"';} ?>
<?php if($orderfield=='ordergrade'){$grade = ' selected="selected"';} ?>

<select name="order">
    <option value="ordersessionid" <?php echo $session; ?>>Session ID</option>
    <option value="ordermoduleid" <?php echo $module; ?>>Module Number</option>
    <option value="orderteacherid" <?php echo $teacher; ?>>Teacher Username</option>
    <option value="orderstudentid" <?php echo $student; ?>>Student Username</option>
    <option value="ordergrade" <?php echo $grade; ?>>Grade</option>
 </select>

关于php - 提交表单后如何使下拉菜单值仍处于选中状态？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/7780297/

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