mysql - "almost"重复条目的 SQL 查询(最后 3 列的值相同)

Question

我需要有关 SQL 查询的帮助。我有一个包含许多条目的表，我想查询最后 3 列具有相同值的所有条目。

我的表格如下所示:

|Refrigator|98C08A|2011-08-06 00:00:30|126|126
|Refrigator|B7BE29|2011-08-06 00:00:30|73|70
|Refrigator|599393|2011-08-06 00:00:30|126|126
|Refrigator|B7BE29|2011-08-06 00:00:29|73|70
|Refrigator|599393|2011-08-06 00:00:29|126|126
|Refrigator|599393|2011-08-06 00:00:29|126|126
|Refrigator|98C08A|2011-08-06 00:00:29|126|126
|Refrigator|98C08A|2011-08-06 00:00:29|126|126
|Refrigator|599393|2011-08-06 00:00:28|126|126

所以我想获取最后 3 列具有完全相同值的所有行，因此结果应该如下所示:

|Refrigator|98C08A|2011-08-06 00:00:30|126|126
|Refrigator|599393|2011-08-06 00:00:30|126|126
|Refrigator|599393|2011-08-06 00:00:29|126|126
|Refrigator|599393|2011-08-06 00:00:29|126|126 (if possible without this duplicate)
|Refrigator|98C08A|2011-08-06 00:00:29|126|126
|Refrigator|98C08A|2011-08-06 00:00:29|126|126 (if possible without this duplicate)

有没有人知道如何管理它？到目前为止我尝试的是:

SELECT * 
FROM smtab 
WHERE Datetime IN (
      SELECT Datetime 
      FROM smtab 
      GROUP BY Datetime 
      HAVING count(Datetime) >1) 
AND Power1 IN (
      SELECT Power1 
      FROM smtab 
      GROUP BY Power1 
      HAVING count(Power1) >1) 
AND Power8 IN (
      SELECT Power8 
      FROM smtab 
      GROUP BY Power8 
      HAVING count(Power8) >1) 
ORDER BY Datetime DESC;

但我没有工作!!!

希望有人能帮助我!提前谢谢...

Answer 1

SELECT DISTINCT *
FROM   smtab NATURAL JOIN (
  SELECT   Datetime, Power1, Power8
  FROM     smtab
  GROUP BY Datetime, Power1, Power8
  HAVING   COUNT(*) > 1
) AS t