php - 将 jquery 添加到基于 php mysql 的分页

Question

我正在一个基于 PHP-Mysql 的网站上工作，该网站有一些要显示的大列表(例如产品列表)。为了方便用户，现在我不得不将其分解为页面。所以我使用 PHP 添加了分页.现在我每次点击页码都会刷新页面。所以我有一个 PHP/MySQL 的基础，想添加 Ajax/jquery 来避免不必要的页面刷新。如何将分页添加到我现有的代码中？？这是供引用的 php 代码。

        <div class="flt width710">
            <div style="margin-top:10px;" class="flt mapnewalert"> <?php //echo ucfirst($_SESSION['$city']) ?></div>
            <div style="float:right" id="toppagesel">
            <?php 
                    echo $pages->display_pages();
                    echo $pages->display_items_per_page();
                    //echo "<span class=\"\">".$pages->display_jump_menu()."</span>";
                    $query = "SELECT * from properties,locality,cities where properties.city_id='".$_SESSION['$cityId']."' and properties.locality_id=locality.locality_id and properties.city_id=cities.city_id $pages->limit";
                    $result = mysql_query($query) or die(mysql_error());

                    //$getProperty =    $propertyDetails->getPropertyDetailsByCityIdPaginate($_SESSION['$cityId'],$limit);
            ?>
            <?php //echo $pages->display_pages(); ?><?php //echo $pages->display_items_per_page();?>
            </div>
        </div>

和分页类:

         class Paginator{
var $items_per_page;
var $items_total;
var $current_page;
var $num_pages;
var $mid_range;
var $low;
var $limit;
var $return;
var $default_ipp;
var $querystring;
var $ipp_array;

          function Paginator()
{
    $this->current_page = 1;
    $this->mid_range = 2;
    $this->ipp_array = array(2,4,6,8,'All');
    $this->items_per_page = (!empty($_GET['ipp'])) ? $_GET['ipp']:$this->default_ipp;
}

          function paginate()
{
    if(!isset($this->default_ipp)) $this->default_ipp=2;
    if($_GET['ipp'] == 'All')
    {
        $this->num_pages = 1;
          //    $this->items_per_page = $this->default_ipp;
    }
    else
    {
        if(!is_numeric($this->items_per_page) OR $this->items_per_page <= 0) $this->items_per_page = $this->default_ipp;
        $this->num_pages = ceil($this->items_total/$this->items_per_page);
    }
    $this->current_page = (isset($_GET['page'])) ? (int) $_GET['page'] : 1 ; // must be numeric > 0
    $prev_page = $this->current_page-1;
    $next_page = $this->current_page+1;
    if($_GET)
    {
        $args = explode("&",$_SERVER['QUERY_STRING']);
        foreach($args as $arg)
        {
            $keyval = explode("=",$arg);
            if($keyval[0] != "page" And $keyval[0] != "ipp") $this->querystring .= "&" . $arg;
        }
    }

    if($_POST)
    {
        foreach($_POST as $key=>$val)
        {
            if($key != "page" And $key != "ipp") $this->querystring .= "&$key=$val";
        }
    }
    if($this->num_pages > 4)
    {
        $this->return = ($this->current_page > 1 And $this->items_total >= 10) ? "<a class=\"paginate\" href=\"$_SERVER[PHP_SELF]?page=$prev_page&ipp=$this->items_per_page$this->querystring\">&laquo; Previous</a> ":"<span class=\"inactive\" href=\"#\">&laquo; Previous</span> ";

        $this->start_range = $this->current_page - floor($this->mid_range/2);
        $this->end_range = $this->current_page + floor($this->mid_range/2);

        if($this->start_range <= 0)
        {
            $this->end_range += abs($this->start_range)+1;
            $this->start_range = 1;
        }
        if($this->end_range > $this->num_pages)
        {
            $this->start_range -= $this->end_range-$this->num_pages;
            $this->end_range = $this->num_pages;
        }
        $this->range = range($this->start_range,$this->end_range);

        for($i=1;$i<=$this->num_pages;$i++)
        {
            if($this->range[0] > 2 And $i == $this->range[0]) $this->return .= " ... ";
            // loop through all pages. if first, last, or in range, display
            if($i==1 Or $i==$this->num_pages Or in_array($i,$this->range))
            {
                $this->return .= ($i == $this->current_page And $_GET['page'] != 'All') ? "<a title=\"Go to page $i of $this->num_pages\" class=\"current\" href=\"#\">$i</a> ":"<a class=\"paginate\" title=\"Go to page $i of $this->num_pages\" href=\"$_SERVER[PHP_SELF]?page=$i&ipp=$this->items_per_page$this->querystring\">$i</a> ";
            }
            if($this->range[$this->mid_range-1] < $this->num_pages-1 And $i == $this->range[$this->mid_range-1]) $this->return .= " ... ";
        }
        $this->return .= (($this->current_page < $this->num_pages And $this->items_total >= 10) And ($_GET['page'] != 'All') And $this->current_page > 0) ? "<a class=\"paginate\" href=\"$_SERVER[PHP_SELF]?page=$next_page&ipp=$this->items_per_page$this->querystring\">Next &raquo;</a>\n":"<span class=\"inactive\" href=\"#\">&raquo; Next</span>\n";
        $this->return .= ($_GET['page'] == 'All') ? "<a class=\"current\" style=\"margin-left:10px\" href=\"#\">All</a> \n":"<a class=\"paginate\" style=\"margin-left:10px\" href=\"$_SERVER[PHP_SELF]?page=1&ipp=All$this->querystring\">All</a> \n";
    }
    else
    {
        for($i=1;$i<=$this->num_pages;$i++)
        {
            $this->return .= ($i == $this->current_page) ? "<a class=\"current\" href=\"#\">$i</a> ":"<a class=\"paginate\" href=\"$_SERVER[PHP_SELF]?page=$i&ipp=$this->items_per_page$this->querystring\">$i</a> ";
        }
        $this->return .= "<a class=\"paginate\" href=\"$_SERVER[PHP_SELF]?page=1&ipp=All$this->querystring\">All</a> \n";
    }
    $this->low = ($this->current_page <= 0) ? 0:($this->current_page-1) * $this->items_per_page;
    if($this->current_page <= 0) $this->items_per_page = 0;
    $this->limit = ($_GET['ipp'] == 'All') ? "":" LIMIT $this->low,$this->items_per_page";
}

   }

我怎样才能实现它？我引用了其他线程并尝试了但无法在我的上下文中工作。我是 ajax jquery 部分的新手，如果它是一个简单的任务，我很抱歉! :P

PS:在当前情况下这可能吗，还是我必须更改我的分页类和 php 代码。请说明一下!!
谢谢

Answer 1

有许多 JavaScript 分页库将帮助您简化您的工作，

你能试试这个分页库吗，

演示:http://www.frequency-decoder.com/demo/table-sort-revisited/paginate/

网站:http://www.frequency-decoder.com/2007/10/19/client-side-table-pagination-script/