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java - 没有日期的排序时间

转载 作者:行者123 更新时间:2023-11-29 03:04:24 26 4
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我正在尝试解决以下问题:https://www.codeeval.com/browse/214/下面是我的代码和输出: 代码

public class TimeSort implements Comparable<TimeSort>{
public int hour;
public int minutes;
public int seconds;

public TimeSort(int hour, int minutes, int seconds) {
this.hour = hour;
this.minutes = minutes;
this.seconds = seconds;
}

public TimeSort(String str){
/*DateFormat formatter = new SimpleDateFormat("HH:mm:ss");
final String x = str;
try {
Date time = sdf.parse(x);

//Time time = new Time(new SimpleDateFormat("HH:mm:ss").parse(x).getTime());
this.hour = time.getHours();
this.minutes = time.getMinutes();
this.seconds = time.getSeconds();
} catch (ParseException e) {
e.printStackTrace();
}*/

String[] parts = str.split(":");
int hour = Integer.parseInt(parts[0]);
int minutes = Integer.parseInt(parts[1]);
int seconds = Integer.parseInt(parts[2]);

this.hour = hour;
this.minutes = minutes;
this.seconds = seconds;
}

public int getHour() {
return hour;
}

public void setHour(int hour) {
this.hour = hour;
}

public int getMinutes() {
return minutes;
}

public void setMinutes(int minutes) {
this.minutes = minutes;
}

public int getSeconds() {
return seconds;
}

public void setSeconds(int seconds) {
this.seconds = seconds;
}

@Override
public String toString() {
if(this.getHour() < 10){
return "0"+this.getHour()+":"+this.getSeconds()+":"+this.getSeconds();
}

return this.getHour()+":"+this.getSeconds()+":"+this.getSeconds();
}

public static void main(String[] args){

List<String> inputs = new ArrayList<>();
inputs.add("02:26:31 14:44:45 09:53:27");
inputs.add("05:33:44 21:25:41");
inputs.add("02:26:31 14:44:45 09:53:27 02:26:31 01:44:45 19:53:27");

for (String input : inputs){
sortTimes(input);
}

@Override
public int compareTo(TimeSort timeSort) {
if(this.getHour() > timeSort.getHour()){
return -1;
}
else if(this.getHour() < timeSort.getHour()){
return 1;
}
else if(this.getHour() == timeSort.getHour()) {
if(this.getMinutes() > timeSort.getMinutes()){
return -1;
}
else if(this.getMinutes() < timeSort.getMinutes()){
return 1;
}
}
else if(this.getSeconds() > timeSort.getSeconds()){
return 1;
}

return 0;
}

public static void sortTimes(String str){
List<TimeSort> list = new ArrayList<>();
String[] times = str.split(" ");

for (String time : times){
list.add(new TimeSort(time));
}

System.out.print("Before Sorting: ");
for (TimeSort t : list){
System.out.print(t + " ");
}
System.out.println();
Collections.sort(list);
System.out.print("After Sorting: ");
for (TimeSort t : list){
System.out.print(t + " ");
}
System.out.println();
System.out.println("==============================================================");
}
}

输出

Before Sorting: 02:31:31 14:45:45 09:27:27 
After Sorting: 14:45:45 09:27:27 02:31:31
==============================================================
Before Sorting: 05:44:44 21:41:41
After Sorting: 21:41:41 05:44:44
==============================================================
Before Sorting: 02:31:31 14:45:45 09:27:27 02:31:31 01:45:45 19:27:27
After Sorting: 19:27:27 14:45:45 09:27:27 02:31:31 02:31:31 01:45:45
==============================================================

我看到的奇怪事情是时间打印不正确。例如 02:26:31 打印为 02:31:31。即使我试图解析字符串时间也是一样的(代码的注释部分)

感谢任何帮助。谢谢

最佳答案

您的 toString() 方法有一个错误:

@Override
public String toString() {
if(this.getHour() < 10){
return "0"+this.getHour()+":"+this.getSeconds()+":"+this.getSeconds();
}

return this.getHour()+":"+this.getSeconds()+":"+this.getSeconds();
}

请注意,第二个字段是 getSeconds() 而不是 getMinutes()

关于java - 没有日期的排序时间,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/32784814/

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