gpt4 book ai didi

mysql - 如何在mysql中做一个简单的子查询

转载 作者:行者123 更新时间:2023-11-29 03:03:49 26 4
gpt4 key购买 nike

我有一个这样的表模式

mysql> desc material_out;

`enter code here`+-------------+--------------+------+-----+---------+-------+| Field       | Type         | Null | Key | Default | Extra |+-------------+--------------+------+-----+---------+-------+| id          | int(11)      | NO   |     | 0       |       || barcode     | varchar(20)  | NO   |     | NULL    |       || name        | varchar(100) | NO   |     | NULL    |       || qty         | double       | YES  |     | NULL    |       || unit        | varchar(20)  | YES  |     | NULL    |       || num_letter  | varchar(30)  | YES  |     | NULL    |       || date        | date         | YES  |     | NULL    |       || destination | varchar(50)  | YES  |     | NULL    |       |+-------------+--------------+------+-----+---------+-------+8 rows in set (0.00 sec)

mysql> desc material_in;

`enter code here`+-------------+--------------+------+-----+---------+-------+| Field       | Type         | Null | Key | Default | Extra |+-------------+--------------+------+-----+---------+-------+| id          | int(11)      | NO   |     | 0       |       || barcode     | varchar(20)  | NO   |     | NULL    |       || name        | varchar(100) | NO   |     | NULL    |       || qty         | double       | YES  |     | NULL    |       || unit        | varchar(20)  | YES  |     | NULL    |       || num_letter  | varchar(30)  | YES  |     | NULL    |       || date        | date         | YES  |     | NULL    |       || destination | varchar(50)  | YES  |     | NULL    |       |+-------------+--------------+------+-----+---------+-------+8 rows in set (0.00 sec)

mysql> desc goods;

`enter code here`+-------------+--------------+------+-----+---------+-------+| Field       | Type         | Null | Key | Default | Extra |+-------------+--------------+------+-----+---------+-------+| id          | int(11)      | NO   |     | 0       |       || barcode     | varchar(20)  | NO   |     | NULL    |       || name        | varchar(100) | NO   |     | NULL    |       || unit        | varchar(20)  | YES  |     | NULL    |       || category    | varchar(25)  | YES  |     | NULL    |       || first_stok  | double    )  | YES  |     | NULL    |       |+-------------+--------------+------+-----+---------+-------+6 rows in set (0.00 sec)

In table material_out I have data of 10,000 rows. and has as many as 350 types of barcodes.In table material_in I have data around 15,000 rows. and has as many as 200 types of barcodes.

but i have a problem when doing a query. takes a long time probably about 3 hours.

I think this is not efficient when you want to print a report.

my query like this.

SELECT br.barcode,
out.total_out,
in.total_in,
out.total_out - in.total_in AS RESULT
FROM
(SELECT barcode,
name,
first_stok,
unit
FROM goods
WHERE category=1) AS br
LEFT JOIN
(SELECT
(SELECT sum(qty)
FROM material_out
WHERE date >= '2013-08-15'
AND tanggal <='2013-08-20'
AND barcode=a.barcode) AS total_out
FROM material_out a
GROUP BY a.barcode) AS OUT ON OUT.barcode=br.barcode
LEFT JOIN
(SELECT
(SELECT sum(qty)
FROM material_in
WHERE date >= '2013-08-15'
AND tanggal <='2013-08-20'
AND barcode=a.barcode) AS total_in
FROM material_in a
GROUP BY a.barcode) AS IN ON IN.barcode=br.barcode

编辑了兄弟..来自 realitygone 的新查询。

<pre>
mysql> SELECT tNEW.barcode,
-> tNEW.total_out, tNEW.total_in, tNEW.result,
-> tOLD.total_out AS total_out_old, tOLD.total_in AS total_in_old, tNEW.total_in + tOLD.total_in - tNEW.total_out - tOLD.total_out as sum_total
-> FROM (
-> SELECT goods.barcode,
-> SUM(tOUT.qty) AS total_out,
-> SUM(tIN.qty) AS total_in,
-> SUM(tIN.qty) - SUM(tOUT.qty) AS result
-> FROM goods
-> LEFT JOIN material_out AS tOUT ON tOUT.barcode=goods.barcode
-> LEFT JOIN material_in AS tIN ON tIN.kode=goods.barcode
-> WHERE goods.category=1
-> AND tOUT.date BETWEEN '2013-05-01' AND '2013-08-31'
-> AND tIN.date BETWEEN '2013-05-1' AND '2013-08-31'
-> GROUP BY goods.barcode
-> ) AS tNEW
-> LEFT JOIN (
-> SELECT goods.barcode,
-> SUM(tOUT.qty) AS total_out,
-> SUM(tIN.qty) AS total_in
-> FROM goods
-> LEFT JOIN material_out AS tOUT ON tOUT.barcode=goods.barcode
-> LEFT JOIN material_in AS tIN ON tIN.kode=goods.barcode
-> WHERE goods.category=1
-> AND tOUT.date BETWEEN '2013-01-01' AND '2013-04-31'
-> AND tIN.date BETWEEN '2013-01-01' AND '2013-04-31'
-> GROUP BY goods.barcode
-> ) AS tOLD ON tOLD.barcode=tNEW.barcode;
+-------------+-----------+----------+------------+---------------+-------------------+--------------------+
| barcode | total_out | total_in | result | total_out_old | total_in_old | sum_total |
+-------------+-----------+----------+------------+---------------+-------------------+--------------------+
| CG003 | 2720 | 14400 | 11680 | 17588 | 92160 | 86252 |
| CG009 | 144 | 720 | 576 | NULL | NULL | NULL |
| CG010 | 596 | 1800 | 1204 | 1512 | 6048 | 5740 |
| CG011 | 864 | 4320 | 3456 | 1156 | 3600 | 5900 |
| CG012 | 1875 | 7560 | 5685 | 843 | 4680 | 9522 |
| CG013 | 2520 | 7560 | 5040 | 2826 | 14400 | 16614 |
| CG014 | 19320 | 314340 | 295020 | 39312 | 597312 | 853020 |
| CG015 | 890 | 9750 | 8860 | 12003 | 183330 | 180187 |
| CG017 | 24 | 102000 | 101976 | 26 | 420 | 102370 |
| CG018 | 390000 | 273000 | -117000 | 1320000 | 1020000 | -417000 |
| CG020 | 396 | 2170 | 1774 | 820 | 3656 | 4610 |
| CG022 | 238 | 1200 | 962 | 330 | 800 | 1432 |
| CG023 | 752 | 3600 | 2848 | 3585 | 21600 | 20863 |
| CG024 | 21560 | 146068 | 124508 | 64095 | 361552.6000000002 | 421965.6000000002 |
| CG025 | 14833 | 85992 | 71159 | 49049 | 230218.0000000009 | 252328.00000000093 |
| CG026 | 172 | 4000 | 3828 | 766 | 1170 | 4232 |
| CG028 | 126 | 1440 | 1314 | 41 | 660 | 1933 |
| CG029 | 18 | 300 | 282 | 40 | 920 | 1162 |
| CG030 | 50 | 720 | 670 | 50 | 780 | 1400 |
| CHDRY001 | 10260 | 81000 | 70740 | 73440 | 936000 | 933300 |
| CHDRY002 | 4071288 | 3477926 | -593362 | 9762598 | 8570238 | -1785722 |
| CHDRY003 | 8880 | 4441 | -4439 | NULL | NULL | NULL |
| CHDRY004 | 48960 | 238590 | 189630 | 119880 | 413850 | 483600 |
| CHDRY005 | 144 | 144 | 0 | 256 | 256 | 0 |
| CHDRY006 | 37440 | 211200 | 173760 | 164160 | 968000 | 977600 |
| CHDRY007 | 237600 | 1679040 | 1441440 | 604890 | 4758600 | 5595150 |
| CHDRY009 | 766080 | 2026160 | 1260080 | 698250 | 2151560 | 2713390 |
| CHDRY010 | 3600 | 168000 | 164400 | 40800 | 1488000 | 1611600 |
| CHDRY012 | 200 | 2700 | 2500 | 340 | 5600 | 7760 |
| CHDRY013 | 4290 | 17600 | 13310 | 4290 | 21120 | 30140 |
| CHDRY014 | 278300 | 643720 | 365420 | 466210 | 1243620 | 1142830 |
| CHDRY015 | 78720 | 264100 | 185380 | 81840 | 367070 | 470610 |
| CHDRY018 | 2431270 | 1987260 | -444010 | 4877450 | 4672689 | -648771 |
| CHDRY022 | 1320 | 4840 | 3520 | 330 | 1650 | 4840 |
| CHDRY023 | 200 | 110 | -90 | NULL | NULL | NULL |
| CHDRY024 | 2000 | 4000 | 2000 | 100 | 100 | 2000 |
| CHDRY025 | 1800 | 4000 | 2200 | NULL | NULL | NULL |
| CHDRY026 | 850 | 850 | 0 | NULL | NULL | NULL |
| CHDRY028 | 120 | 480 | 360 | NULL | NULL | NULL |
| CHPRINT001 | 8000 | 222000 | 214000 | 13800 | 390000 | 590200 |
| CHPRINT002 | 4000 | 10000 | 6000 | 4200 | 21000 | 22800 |
| CHPRINT004 | 13600 | 324000 | 310400 | 14400 | 512000 | 808000 |
| CHPRINT005 | 28800 | 136800 | 108000 | 35000 | 133000 | 206000 |
| CHPRINT006 | 3100 | 93000 | 89900 | 5600 | 112000 | 196300 |
| CHPRINT007 | 16800 | 69000 | 52200 | 2000 | 9000 | 59200 |
------------------------------------------------------------------------------------------------------------
</pre>

你好,我有新问题。当我计算字段 tNEW.total_in + tOLD.total_in - tNEW.total_out - tOLD.total_out.当遇到列包含 null 时,则求和的结果包含 null。例如在条码CHDRY025条码CHDRY003条码CHDRY028条码NWDRY004

对于管理员或版主,抱歉,如果我违反了规则。 :-)

====================== 2013 年 9 月 30 日编辑后 ==================== ==================

你好RealityGone,我使用了您的查询。结果进展顺利。但是当我尝试输入新数据时。然后我重新查询你的显示。但结果与输入的数据不一致。例如,当我输入您的查询时。结果如下

+----------------------+-----------+----------+------------+---------------+-------------------+|    barcode           | total_out | total_in | result     | total_out_old | total_in_old      |+----------------------+-----------+----------+------------+---------------+-------------------+| TNWET021             |      6195 |    15000 |       8805 |         20085 |             46200 || TNWET020             |      3420 |     7650 |       4230 |          4860 |             23925 || TNWET019             |      8370 |    25200 |      16830 |         11610 |             47175 || TNWET018             |     18690 |    44100 |      25410 |         13800 |             54150 || TNWET017             |      1140 |     3750 |       2610 |          3690 |             16200 || TNWET016             |     19500 |    56100 |      36600 |         31725 |            111300 || TNWET015             |      5145 |    18150 |      13005 |          6510 |             23400 || TNWET014             |     33300 |    65250 |      31950 |         96300 |            262500 || TNWET013             |      1170 |     5625 |       4455 |          3690 |             13200 || TNWET012             |       720 |     2700 |       1980 |          3870 |             13800 || TNWET011             |         0 |        0 |          0 |           180 |               450 || TNWET010             |         0 |        0 |          0 |           405 |              1125 || TNWET009             |         0 |        0 |          0 |             0 |                 0 |

当我进行手动求和并得到这样的结果时。

mysql> select sum(qty) from material_in where barcode='TNWET021' and date BETWEEN '2013-05-01' AND '2013-08-31';+-------------+|   sum(qty)  |+-------------+|         750 |+-------------+1 row in set (0.00 sec)mysql> select sum(qty) from material_in where barcode='TNWET020' and date BETWEEN '2013-05-01' AND '2013-08-31';+-------------+|   sum(qty)  |+-------------+|         450 |+-------------+1 row in set (0.00 sec)

最佳答案

我认为您的查询甚至没有完成我认为应该做的事情。您没有在问题中指定您期望的输出,但我假设您想要 cargo 表中每个条形码的两个 Material 表中数量字段的 SUM()。 (我还假设“tanggal”字段与其上方的日期字段相同,因为它不在您的 EXPLAIN 输出中,它表示英文日期。)

您当然不需要要连接的表表达式的 SELECT 语句中的子查询。我也不明白为什么这些根本需要是表表达式。我对查询运行得非常慢并不感到惊讶。它是连接表表达式中的相关子查询。

我认为您根本不需要子查询。这是我的简化版本:

SELECT goods.barcode,
SUM(tOUT.qty) AS total_out,
SUM(tIN.qty) AS total_in,
SUM(tOUT.qty)-SUM(tIN.qty) AS result
FROM (

商品 LEFT JOIN material_out AS tOUT ON tOUT.barcode=goods.barcode LEFT JOIN material_in AS tIN ON tIN.barcode=goods.barcode 其中 g.category=1 AND tOUT.date BETWEEN '2013-08-15' AND '2013-08-20' AND tIN.date BETWEEN '2013-08-15' AND '2013-08-20' GROUP BY g.条形码

可能有更好的方法来执行此操作,但这就是我如何像您要求的那样快速将两个日期范围放在一起:

SELECT tNEW.barcode,
tNEW.total_out, tNEW.total_in,
tNEW.total_out-tNEW.total_in AS result,
COALESCE(tOLD.total_out,0) AS total_out_old, COALESCE(tOLD.total_in,0) AS total_in_old
FROM (
SELECT g.barcode,
COALESCE(SUM(tOUT.qty),0) AS total_out,
COALESCE(SUM(tIN.qty),0) AS total_in
FROM (
SELECT DISTINCT barcode
FROM goods
) AS g
LEFT JOIN material_out AS tOUT ON tOUT.barcode=g.barcode
LEFT JOIN material_in AS tIN ON tIN.barcode=g.barcode
WHERE g.category=1
AND tOUT.date BETWEEN '2013-08-15' AND '2013-08-20'
AND tIN.date BETWEEN '2013-08-15' AND '2013-08-20'
GROUP BY g.barcode
) AS tNEW
LEFT JOIN (
SELECT g.barcode,
SUM(tOUT.qty) AS total_out,
SUM(tIN.qty) AS total_in
FROM (
SELECT DISTINCT barcode
FROM goods
) AS g
LEFT JOIN material_out AS tOUT ON tOUT.barcode=g.barcode
LEFT JOIN material_in AS tIN ON tIN.barcode=g.barcode
WHERE g.category=1
AND tOUT.date BETWEEN '2013-01-01' AND '2013-04-31'
AND tIN.date BETWEEN '2013-01-01' AND '2013-04-31'
GROUP BY g.barcode
) AS tOLD ON tOLD.barcode=tNEW.barcode

关于mysql - 如何在mysql中做一个简单的子查询,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/18996445/

26 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com