Java 用空白分隔符分割字符串

Question

我有一个字符串女巫，我想拆分。我唯一的分隔符是空格。看起来像这样:12 鲍勃马利 22/01/15 0 0 1 1 0

我用这个:

line = br1.readLine();
String[] parts = line.split(" ");
String number    = parts[0]; 
String reference = parts[1]; 
String date      = parts[2];
String one       = parts[3];
String sd        = parts[4];
String dd        = parts[5];
String tt        = parts[6];
String vs        = parts[7];
System.out.println(
 "No:"+number+"Ref:"+reference+"Date:"+date+"One:"+one+"Sd:"+sd+"Dd:"+dd+"Tt:"+tt+"Vs:"+vs);

结果是:

No:12 Ref:BobMarley Date:22/01/15 One:0 Sd:0 Dd:1 Tt:1 Vs:0

如预期。一切都好。

现在，我的问题是字符串是:12 Bob Marley 22/01/15 0 0 1 1 0

或:12 哈利波特与乐队 22/01/15 0 0 1 1 0

输出将是:

No:12 Ref:Bob Date:Marley One:22/01/15 Sd0 Dd:0 Tt:1 Vs:1

预期:12 引用:Bob Marley 日期:22/01/15 ......

知道如何只修剪“否”之间的空白。和“日期”？或者任何其他想法如何获得干净的“Ref”，无论里面有多少个单词。谢谢你!

Answer 1

我建议首先使用正则表达式拆分行以捕获引用部分，然后使用空格拆分以获得结果:

String line = "12 Bob Marley 22/01/15 0 0 1 1 0";

    String pattern = "([0-9]+)([a-zA-z|' ']+)(.*)";

    Pattern r = Pattern.compile(pattern);
    Matcher m = r.matcher(line);

    if(m.find()) {
        System.out.println("No:" + m.group(1));//this will get 12
        System.out.println("ref:" + m.group(2));//this will get the name
        String[] parts = m.group(3).split(" ");//this is the rest
        String date      = parts[0];
        String one       = parts[1];
        String sd        = parts[2];
        String dd        = parts[3];
        String tt        = parts[4];
        String vs        = parts[5];
        System.out.println("Date:"+date+"One:"+one+"Sd:"+sd+"Dd:"+dd+"Tt:"+tt+"Vs:"+vs);
    }