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选择中的 MySQL datediff

转载 作者:行者123 更新时间:2023-11-29 02:51:55 24 4
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我有 2 个 mySQL 请求,我需要在我的第一个请求中包含我的 DATEDIFF 以显示 user_dateentree 但我不知道该怎么做..

SELECT poste_nom, ups_type_contrat, serv_nom, serv_id_resp 
FROM USER
INNER JOIN USER_POSTE_SERVICE
ON USER.user_id= USER_POSTE_SERVICE.ups_poste_id
INNER JOIN POSTE
ON USER_POSTE_SERVICE. ups_poste_id = POSTE.poste_id
INNER JOIN SERVICE
ON USER_POSTE_SERVICE.ups_id_serv = SERVICE.serv_id
WHERE user_id = 2
ORDER BY user_nom ASC

SELECT FLOOR( DATEDIFF( CURDATE( ) , user_dateentree ) /365 )
FROM USER

最佳答案

就这样

SELECT poste_nom, ups_type_contrat, serv_nom, serv_id_resp,
FLOOR( DATEDIFF( CURDATE( ) , user_dateentree ) /365 ) as 'datediff'
FROM USER
INNER JOIN USER_POSTE_SERVICE
ON USER.user_id= USER_POSTE_SERVICE.ups_poste_id
INNER JOIN POSTE
ON USER_POSTE_SERVICE. ups_poste_id = POSTE.poste_id
INNER JOIN SERVICE
ON USER_POSTE_SERVICE.ups_id_serv = SERVICE.serv_id
WHERE user_id = :idSalarie
ORDER BY user_nom ASC

关于选择中的 MySQL datediff,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/34747556/

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