json - Elasticsearch - 从 json 响应中排除索引和类型

Question

当我对这样的索引执行查询时:

{
   "_source":["bar"] , "size":100,
   "query": {
       "match_all": {}
   },
   "filter": {
       "type" : {
           "value" : "foo"
        }
    }
}

response包括index，type等，但是index和type我已经知道了，因为我指定了。此信息只会膨胀 json 数据的大小。有没有办法从响应中排除这些？

这是我得到的:

{
"took": 31,
"timed_out": false,
"_shards": {
    "total": 5,
    "successful": 5,
    "failed": 0
    },
"hits": {
    "total": 364024,
    "max_score": 1,
    "hits": [
          {
        "_index": "foo_bar",
        "_type": "foo",
        "_id": "asdjj123123",
        "_score": 1,
        "_source": {
          "bar": "blablablabla"
    }
  }
,...

我想要的是这样的，所以没有type,score,index的响应:

{
"took": 31,
"timed_out": false,
"_shards": {
    "total": 5,
    "successful": 5,
    "failed": 0
    },
"hits": {
    "total": 364024,
    "max_score": 1,
    "hits": [
          {
        "_id": "asdjj123123",
        "_source": {
          "bar": "blablablabla"
    }
  }
,...

Answer 1

是的，从 ES 1.6 开始，您可以使用 response filtering并在查询中使用 filter_path 参数仅枚举您在响应中需要的内容:

curl -XGET 'localhost:9200/foo_bar/foo/_search?pretty&filter_path=hits.total,hits.max_score,hits.hits._id,hits.hits._source'