elasticsearch - 如何通过 JSON 将查询设置为 Elasticsearch SearchRequest？

Question

Elasticsearch :6.1.2

我有一个通过 JSON 的输入查询，我想使用 high level Java API使用该查询数据构建搜索请求。

String jsonQuery = "..."
SearchRequest searchRequest = new SearchRequest()
SearchSourceBuilder builder = ?
searchRequest.source(builder);

我尝试通过以下方式构建生成器:

SearchSourceBuilder.fromXContent(XContentType.JSON.xContent().createParser(NamedXContentRegistry.EMPTY, query));

但这会产生:

Caused by: org.elasticsearch.ElasticsearchException: namedObject is not supported for this parser at org.elasticsearch.common.xcontent.NamedXContentRegistry.parseNamedObject(NamedXContentRegistry.java:129) ~[elasticsearch-6.1.2.jar:6.1.2] at org.elasticsearch.common.xcontent.support.AbstractXContentParser.namedObject(AbstractXContentParser.java:402) ~[elasticsearch-6.1.2.jar:6.1.2] at org.elasticsearch.index.query.AbstractQueryBuilder.parseInnerQueryBuilder(AbstractQueryBuilder.java:313) ~[elasticsearch-6.1.2.jar:6.1.2] at org.elasticsearch.search.builder.SearchSourceBuilder.parseXContent(SearchSourceBuilder.java:1003) ~[elasticsearch-6.1.2.jar:6.1.2] at org.elasticsearch.search.builder.SearchSourceBuilder.fromXContent(SearchSourceBuilder.java:115) ~[elasticsearch-6.1.2.jar:6.1.2]

Answer 1

我现在以这种方式生成 SearchSourceBuilder:

String query = "..."
SearchSourceBuilder searchSourceBuilder = new SearchSourceBuilder();
SearchModule searchModule = new SearchModule(Settings.EMPTY, false, Collections.emptyList());
try (XContentParser parser = XContentFactory.xContent(XContentType.JSON).createParser(new NamedXContentRegistry(searchModule
            .getNamedXContents()), query)) {
    searchSourceBuilder.parseXContent(parser);
}