ios - 联系人排序类似于 viber iOS App

Question

我正在尝试过滤我的联系人，类似于 Viber iOS 应用程序。通过切换分段控制分为“所有”和“仅限应用程序用户”两类来列出联系人。

获取联系人列表时，如果联系人数量较多，则需要更多时间。

目前我正在手动运行 for-loop 来获取联系人，如果有任何其他替代方法，请告诉我。

`-(void)usersList:(NSMutableDictionary *) dictUsrs    
{
NSDictionary *contactDetails;
arrContactsUser = [[NSMutableArray alloc] init];
[arrContactsUser removeAllObjects];
NSArray *sorted = [[sectionForRecievedContacts allKeys] sortedArrayUsingComparator:^NSComparisonResult(id obj1, id obj2) {
    //             NSOrderedAscending, NSOrderedSame, NSOrderedDescending
    BOOL isPunct1 = [[NSCharacterSet punctuationCharacterSet] characterIsMember:[(NSString*)obj1 characterAtIndex:0]] || [[NSCharacterSet symbolCharacterSet] characterIsMember:[(NSString*)obj1 characterAtIndex:0]] || [[NSCharacterSet illegalCharacterSet] characterIsMember:[(NSString*)obj1 characterAtIndex:0]] ||
    [[NSCharacterSet whitespaceCharacterSet] characterIsMember:[(NSString*)obj1 characterAtIndex:0]];
    BOOL isPunct2 = [[NSCharacterSet punctuationCharacterSet] characterIsMember:[(NSString*)obj2 characterAtIndex:0]] || [[NSCharacterSet symbolCharacterSet] characterIsMember:[(NSString*)obj2 characterAtIndex:0]] || [[NSCharacterSet illegalCharacterSet] characterIsMember:[(NSString*)obj2 characterAtIndex:0]]||
    [[NSCharacterSet whitespaceCharacterSet] characterIsMember:[(NSString*)obj2 characterAtIndex:0]];

    if (isPunct1 && !isPunct2)
        return NSOrderedDescending;
    else if (!isPunct1 && isPunct2)
        return NSOrderedAscending;

    return [(NSString*)obj1 compare:obj2 options:NSDiacriticInsensitiveSearch|NSCaseInsensitiveSearch];
}];

for (int j=0; j<[[dictUsrs allKeys] count]; j++) {

    for (int i=0; i<[[dictUsrs valueForKey:[sorted objectAtIndex:j]] count]; i++) {

        contactDetails = [[dictUsrs valueForKey:[sorted objectAtIndex:j]] objectAtIndex:i];

        fetchCount++;

        if ([contactDetails objectForKey:@"status"] == nil) {
            NSIndexPath *path = [NSIndexPath indexPathForRow:i inSection:j];
                           if (fetchCount < kFetchLimit) {
                                [self startStatusFetcher:contactDetails forIndexPath:path withTableView:tableViewIngIngUsers];
                    NSLog(@"Fetch for Cell For Row at IndexPath");
            }

        }
        if ([contactDetails objectForKey:@"registered"] != nil && [[contactDetails objectForKey:@"registered"] isEqualToString:@"yes"]) {
            [arrContactsUser addObject:contactDetails];

        }

    }

}
   [self.tableViewIngIngUsers reloadData];

}`

Answer 1

    `dispatch_async(dispatch_get_global_queue(DISPATCH_QUEUE_PRIORITY_HIGH, 0), ^{

});`

dispatch queue 为我提供了临时解决方案，以避免这种长时间的获取延迟。