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我有这个字符串:
<p><span><b>C10373 - FIAT GROUP AUTOMOBILES/RAMO DI AZIENDA DI KUEHNE + NAGEL</b></span>
<p>la somma pari a € 400+IVA per l’attività</p>
<p>TELE+ A 20.000 LIRE AL MESE </p>
<li>a mano o via fax al numero +39.00.0.0.0.00.</li>
<p>Il punteggio base sarà incrementato di un <strong>+ </strong>al ricorrere di ciascuna delle seguenti condizioni:</p>
<li><a href="/aaa/gare/CIGZB81E5568D+RDO1560277+Obblighi+contattuali-signed.pdf" title="">Obblighi contrattuali</a></li>
<li><a href="/aaa/gare/CIGZB81E5568D+RDO1560277+Obblighi+contattuali-signed.pdf" title="">Obblighi contrattuali</a></li>
<li><a href="/aaa/gare/CIGZB81E5568D+RDO_1560277Lettera_Invito.pdf" title="">Lettera di invito</a></li>
<li><a href="/aaa/gare/CIGZB81E5568D+RDO1560277+Obblighi+contattuali-signed.pdf" title="">Obblighi contrattuali</a></li>
<li><a href="/aaa/gare/CIGZB81E5568D+RDO1560277+disciplinare+di+gara-signed.pdf" title="">Disciplinare di gara</a></li>
<li><a href="/aaa/gare/CIGZB81E5568D+determina+di+aggiudicazione+58+2017.pdf" title="">Determina di aggiudicazione</a></li>
那是我记录的html内容的一部分。
现在,我的问题是我试图只替换 href 标签中的“+”,所以我在 MySQL 中创建了这个脚本:
set @xxx = replace(
@xxx,
substr(@xxx,locate('<a href',@xxx)+3,locate('</a>',@xxx)-locate('<a href',@xxx)),
replace(
substr(
@xxx,
locate('<a href',@xxx)+3,
locate('</a>',@xxx)-locate('<a href',@xxx)
),
'+',
' ')
);
@xxx 是有问题的字符串。头是<a href
尾部是</a>
,这永远不会改变。
但我得到了这个结果,只改变了与第一个相同的子串,因为脚本只搜索具有相同中心部分的其他子串:
<p><span><b>C10373 - FIAT GROUP AUTOMOBILES/RAMO DI AZIENDA DI KUEHNE + NAGEL</b></span>
<p>la somma pari a € 400+IVA per l’attività</p>
<p>TELE+ A 20.000 LIRE AL MESE </p>
<li>a mano o via fax al numero +39.06.85.82.12.56.</li>
<p>Il punteggio base sarà incrementato di un <strong>+ </strong>al ricorrere di ciascuna delle seguenti condizioni:</p>
<li><a href="/aaa/gare/CIGZB81E5568D RDO1560277 Obblighi contattuali-signed.pdf" title="">Obblighi contrattuali</a></li>
<li><a href="/aaa/gare/CIGZB81E5568D RDO1560277 Obblighi contattuali-signed.pdf" title="">Obblighi contrattuali</a></li>
<li><a href="/aaa/gare/CIGZB81E5568D+RDO_1560277Lettera_Invito.pdf" title="">Lettera di invito</a></li>
<li><a href="/aaa/gare/CIGZB81E5568D RDO1560277 Obblighi contattuali-signed.pdf" title="">Obblighi contrattuali</a></li>
<li><a href="/aaa/gare/CIGZB81E5568D+RDO1560277+disciplinare+di+gara-signed.pdf" title="">Disciplinare di gara</a></li>
<li><a href="/aaa/gare/CIGZB81E5568D+determina+di+aggiudicazione+58+2017.pdf" title="">Determina di aggiudicazione</a></li>
我必须替换 href 标签中的所有“+”,而不替换其他地方的“+”,例如“€ 400+IVA”或“al numero +39.00.0.0.0.00”中的“+”。 .
提前感谢您的帮助,我希望这个问题不是那么神秘^^。
最佳答案
只有在不使用完整的 HTML 解析器或将 REGEX_REPLACE 函数导入 MySQL 的 UDF 的情况下,才有可能在纯 MySQL 中实现。
诀窍是使用数字生成器并使用嵌套的 SUBSTRING_INDEX 拆分 html 标签上的大字符串
此数字生成器将生成从 1 到 10.000 的数字
所以“解析器”将支持多达 10.000 个标签,如果你需要更多,你需要添加更多
CROSS JOIN (
SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9 UNION SELECT 10
) AS record_[number]
查询
SELECT
(@number := @number + 1) AS number
FROM (
SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9 UNION SELECT 10
) AS record_1
CROSS JOIN (
SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9 UNION SELECT 10
) AS record_2
CROSS JOIN (
SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9 UNION SELECT 10
) AS record_3
CROSS JOIN (
SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9 UNION SELECT 10
) AS record_4
CROSS JOIN ( SELECT @number := 0 ) AS init_user_param
此SQL 语句将用于在html 标记上拆分
SQL语句
CONCAT(SUBSTRING_INDEX(SUBSTRING_INDEX([large_html_string], ">", [tag_position]), ">", -1), ">") as tag
现在的诀窍是结合数字生成器和 html 字符串 splittig。所以 [tag_position] 填充了来自数字生成器的数字。
这是通过 CROSS JOIN 完成的。
查询
SELECT
*
FROM (
SELECT
CONCAT(SUBSTRING_INDEX(SUBSTRING_INDEX(data, ">", generator.number), ">", -1), ">") as tag
FROM (
SELECT '<p><span><b>C10373 - FIAT GROUP AUTOMOBILES/RAMO DI AZIENDA DI KUEHNE + NAGEL</b></span>
<p>la somma pari a € 400+IVA per l’attività</p>
<p>TELE+ A 20.000 LIRE AL MESE </p>
<li>a mano o via fax al numero +39.00.0.0.0.00.</li>
<p>Il punteggio base sarà incrementato di un <strong>+ </strong>al ricorrere di ciascuna delle seguenti condizioni:</p>
<li><a href="/aaa/gare/CIGZB81E5568D+RDO1560277+Obblighi+contattuali-signed.pdf" title="">Obblighi contrattuali</a></li>
<li><a href="/aaa/gare/CIGZB81E5568D+RDO1560277+Obblighi+contattuali-signed.pdf" title="">Obblighi contrattuali</a></li>
<li><a href="/aaa/gare/CIGZB81E5568D+RDO_1560277Lettera_Invito.pdf" title="">Lettera di invito</a></li>
<li><a href="/aaa/gare/CIGZB81E5568D+RDO1560277+Obblighi+contattuali-signed.pdf" title="">Obblighi contrattuali</a></li>
<li><a href="/aaa/gare/CIGZB81E5568D+RDO1560277+disciplinare+di+gara-signed.pdf" title="">Disciplinare di gara</a></li>
<li><a href="/aaa/gare/CIGZB81E5568D+determina+di+aggiudicazione+58+2017.pdf" title="">Determina di aggiudicazione</a></li>' AS data
) AS record
CROSS JOIN (
SELECT
(@number := @number + 1) AS number
FROM (
SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9 UNION SELECT 10
) AS record_1
CROSS JOIN (
SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9 UNION SELECT 10
) AS record_2
CROSS JOIN (
SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9 UNION SELECT 10
) AS record_3
CROSS JOIN (
SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9 UNION SELECT 10
) AS record_4
CROSS JOIN ( SELECT @number := 0 ) AS init_user_param
)
AS generator
)
AS tags
WHERE
tags.tag != '>'
查看演示 http://www.sqlfiddle.com/#!9/de2ed/32
现在我们将标签作为单独的记录,只用包含“href”的记录替换它真的很容易。
SQL语句
(
CASE
WHEN
LOCATE("href", tags.tag) > 0
THEN
REPLACE(tags.tag, "+", " ")
ELSE
tags.tag
END
) AS tag
查看演示 http://www.sqlfiddle.com/#!9/de2ed/38
现在我们知道如何替换,现在我们将把记录合并回一个字符串。我们可以为此使用 GROUP_CONCAT。
查询
SET SESSION group_concat_max_len = @@max_allowed_packet;
SELECT
GROUP_CONCAT(
CASE
WHEN
LOCATE("href", tags.tag) > 0
THEN
REPLACE(tags.tag, "+", " ")
ELSE
tags.tag
END
SEPARATOR ""
) AS html
FROM (
SELECT
CONCAT(SUBSTRING_INDEX(SUBSTRING_INDEX(data, ">", generator.number), ">", -1), ">") as tag
FROM (
SELECT '<p><span><b>C10373 - FIAT GROUP AUTOMOBILES/RAMO DI AZIENDA DI KUEHNE + NAGEL</b></span>
<p>la somma pari a € 400+IVA per l’attività</p>
<p>TELE+ A 20.000 LIRE AL MESE </p>
<li>a mano o via fax al numero +39.00.0.0.0.00.</li>
<p>Il punteggio base sarà incrementato di un <strong>+ </strong>al ricorrere di ciascuna delle seguenti condizioni:</p>
<li><a href="/aaa/gare/CIGZB81E5568D+RDO1560277+Obblighi+contattuali-signed.pdf" title="">Obblighi contrattuali</a></li>
<li><a href="/aaa/gare/CIGZB81E5568D+RDO1560277+Obblighi+contattuali-signed.pdf" title="">Obblighi contrattuali</a></li>
<li><a href="/aaa/gare/CIGZB81E5568D+RDO_1560277Lettera_Invito.pdf" title="">Lettera di invito</a></li>
<li><a href="/aaa/gare/CIGZB81E5568D+RDO1560277+Obblighi+contattuali-signed.pdf" title="">Obblighi contrattuali</a></li>
<li><a href="/aaa/gare/CIGZB81E5568D+RDO1560277+disciplinare+di+gara-signed.pdf" title="">Disciplinare di gara</a></li>
<li><a href="/aaa/gare/CIGZB81E5568D+determina+di+aggiudicazione+58+2017.pdf" title="">Determina di aggiudicazione</a></li>' AS data
) AS record
CROSS JOIN (
SELECT
(@number := @number + 1) AS number
FROM (
SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9 UNION SELECT 10
) AS record_1
CROSS JOIN (
SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9 UNION SELECT 10
) AS record_2
CROSS JOIN (
SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9 UNION SELECT 10
) AS record_3
CROSS JOIN (
SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9 UNION SELECT 10
) AS record_4
CROSS JOIN ( SELECT @number := 0 ) AS init_user_param
)
AS generator
)
AS tags
WHERE
tags.tag != '>'
查看完整查询的演示
关于MySQL 替换 : How replace all occurrences of a char in every distinct substring delimited by the same head and tail,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/49560296/
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