mysql - SQL where查询到IN条件的第一行

Question

我有这个 SQL 查询:

SELECT (CASE WHEN count(_days) > 0 THEN 'yes' ELSE 'No' END) as availability 
  FROM ( 
        SELECT count(roomTypeDay2.room_type_id) as _days  
          FROM room_type_day as roomTypeDay2 
     LEFT JOIN room_type as roomType2 on roomTypeDay2.room_type_id = roomType2.id  
         WHERE roomType2.accommodation_id=3 
           AND roomTypeDay2.date IN ( '2018-06-09 00:00:00','2018-06-10 00:00:00','2018-06-11 00:00:00')  
      GROUP BY roomTypeDay2.room_type_id  
        HAVING COUNT(roomTypeDay2.room_type_id) = 3 
       ) as disponible

这工作正常，但现在，我想过滤第一个日期行 (2018-06-09 00:00:00) 是否有

"min_night_stay <= 3 and release_days <=2"

参数，但我不知道怎么做。

我尝试将这些行添加到查询中:

AND (roomTypeDay2.date = '2018-06-09 00:00:00' and roomTypeDay2.min_night_stay <= 3 AND roomTypeDay2.release_days <= 2)

但这不是正确的查询。

更新

 SELECT (CASE WHEN count(_days) > 0 THEN 'yes' ELSE 'No' END) as availability 
   FROM ( 
        SELECT count(roomTypeDay2.room_type_id) as _days  
          FROM room_type_day as roomTypeDay2 
     LEFT JOIN room_type as roomType2 on roomTypeDay2.room_type_id = roomType2.id  
           AND roomType2.accommodation_id=3 
         WHERE roomTypeDay2.date IN ( '2018-06-09 00:00:00','2018-06-10 00:00:00','2018-06-11 00:00:00')  
      GROUP BY roomTypeDay2.room_type_id  
        HAVING COUNT(roomTypeDay2.room_type_id) = 3 
         ) as disponible

---

解决方案

SELECT (CASE WHEN count(_days) > 0 THEN 'yes' ELSE 'No' END) as availability 
    FROM ( 
        SELECT count(roomTypeDay2.room_type_id) as _days  
        FROM room_type_day as roomTypeDay2  
        LEFT JOIN room_type as roomType2 on roomTypeDay2.room_type_id = roomType2.id 
        WHERE roomType2.accommodation_id=3 
        AND roomTypeDay2.num_rooms_available > 0  
        AND (roomTypeDay2.date = '2018-06-12 00:00:00' AND roomTypeDay2.min_night_stay <= 2 AND roomTypeDay2.release_days <= 2 )
        OR roomTypeDay2.date IN ( '2018-06-13 00:00:00','2018-06-14 00:00:00')  
        GROUP BY roomTypeDay2.room_type_id  
        HAVING COUNT(roomTypeDay2.room_type_id) = 3 
    ) as disponible

Answer 1

这是您的 WHERE 子句:

WHERE roomTypeDay2.date IN ('2018-06-09 00:00:00',
                            '2018-06-10 00:00:00',
                            '2018-06-11 00:00:00')  

现在对于第一次约会，您需要额外的标准。为此，使用带括号的 AND 和 OR:

WHERE 
(
  roomTypeDay2.date = '2018-06-09 00:00:00'
  AND
  roomTypeDay2.min_night_stay <= 3 
  AND
  roomTypeDay2.release_days <= 2
)
OR
roomTypeDay2.date IN ('2018-06-10 00:00:00','2018-06-11 00:00:00')