ios - 过滤字典数组时无法解析格式字符串？

Question

我有一个字典数组如下

  <__NSArrayI 0x10053e7c0>(
  {
     busType = "A/C SLEEPER";
     fare = 700;
  },
  {
     busType = "Volvo A/C B9R Multi-Axle Semi Sleeper";
     fare = 500;
  },
  {
     busType = "2+1 Hi-Tech Non A/c";
     fare = 500;
  },
  {
     busType = "Hitech Sleeper Cum Seater";
     fare = 1500;
  },
  {
     busType = "Hi-Tech Non A/c";
     fare = 900;
  },
  {
     busType = "Mercedes Benz Multi Axle";
     fare = 1700;
  })

现在我想根据 busType 键的值来过滤这个数组，即 A/C 或 Non A/c 加上 SLEEPER 。所以我将这些值设置为两个 NSString形成一个谓词，其完成如下。

   -(void)applyFilter:(UIButton *)sender{
   if (ac_Value.length>1&&sleeper_Value.length>1) {

        NSString *dictionaryKey = @"busType";
        NSString *predicateString1 = ac_Value;  // Set this NSString as A/C or Non A/c
        NSString *predicateString2 = sleeper_Value;  //Set this NSString as Sleeper or Non/Sleeper
        NSPredicate* predicate = [NSPredicate predicateWithFormat:@"%K CONTAINS[cd] %@ %@",dictionaryKey,predicateString1,predicateString2];
        NSArray *filteredArray = [busArray filteredArrayUsingPredicate:predicate];
        NSLog(@"filtered array : %@", filteredArray);

    }


 } 

但是，我一直在完成谓词形成部分，该部分给出了如下所示的错误。感谢任何帮助。

     *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: 'Unable to parse the format string "%K CONTAINS[cd] %@ %@"'

Answer 1

如果我没理解错的话，你可能希望你的谓词看起来像这样:

[NSPredicate predicateWithFormat:@"%K CONTAINS[cd] %@ AND %K CONTAINS[cd] %@",dictionaryKey,predicateString1,dictionaryKey,predicateString2];

或者如果 key 始终是 busType，您可以将其缩短为:

[NSPredicate predicateWithFormat:@"busType CONTAINS[cd] %@ AND busType CONTAINS[cd] %@",predicateString1,predicateString2];

但是，将 ac_Value 设置为“A/C”将匹配同时包含“A/C”和“Non A/c”的值。将 [cd] 更改为 [d] 以创建区分大小写/不区分变音的过滤器。