gpt4 book ai didi

android - 改造 - 如何在异步请求中发出同步请求

转载 作者:行者123 更新时间:2023-11-29 02:34:10 27 4
gpt4 key购买 nike

我正在实现一个两级嵌套的 recyclerView 并且两个回收器 View 都使用 retrofit 进行 API 调用。这是发出同步请求的方法:

public void loadSectionStories(String sessionKey, CuratedSection section) {
Call<JsonArray> subCall;
subCall = TravelersApi.endpoint().getCuratedSectionTopics(sessionKey, section.id);

try {
Response<JsonArray> response = subCall.execute();
if(response.code() != 200) {
Toast.makeText(getApplicationContext(), "Cannot load page as of the moment.", Toast.LENGTH_SHORT).show();
return;
}
JsonArray rawStories = response.body();
if(rawStories.size() == 0) {
//TODO: show placeholder
return;
}
ArrayList<CuratedSectionItem> stories = new ArrayList<>();
for(int i = 0; i < rawStories.size(); i++) {
JsonObject jStories = rawStories.get(i).getAsJsonObject();
JSONObject temp = new JSONObject(jStories.toString());
JsonObject author = jStories.get("author").getAsJsonObject();
CuratedSectionItem story = new CuratedSectionItem();
story.title = jStories.get("title").getAsString();
story.avatar = author.get("profile_photo").getAsString();
story.displayPhoto = temp.getString("primary_photo");
story.username = author.get("username").getAsString();
story.description = jStories.get("content").getAsString();
story.topicId = jStories.get("id").getAsString();
story.postId = jStories.get("first_post_id").getAsString();
story.hasReacted = false;
story.upvotes = jStories.get("stats").getAsJsonObject().get("upvotes").getAsInt();
stories.add(story);
}
section.stories = stories;
} catch (IOException e) {
Log.d("ERROR!", e.toString());
e.printStackTrace();
} catch (JSONException e) {
e.printStackTrace();
}
}

这是发出异步请求并在线程中调用 loadSectionStories 的方法:

public void loadCuratedSections(final int start, final int limit) {
SharedPreferences prefs = getSharedPreferences("user_session", MODE_PRIVATE);
final String sessionKey = prefs.getString("session_key", null);

Call<JsonArray> call;
call = TravelersApi.endpoint().getCuratedSections(sessionKey);

call.enqueue(new Callback<JsonArray>() {
@Override
public void onResponse(Call<JsonArray> call, Response<JsonArray> response) {
if(response.code() != 200) {
Toast.makeText(getApplicationContext(), "Cannot load page as of the moment.", Toast.LENGTH_SHORT).show();
return;
}
JsonArray rawSections = response.body();
if(rawSections.size() == 0) {
return;
}
for (int i = start; i < limit; i++) {
JsonObject jSection = rawSections.get(i).getAsJsonObject();
final CuratedSection section = new CuratedSection();
section.id = jSection.get("id").getAsString();
section.header = jSection.get("section_header").getAsString();
section.isShown = jSection.get("is_shown").getAsBoolean();

Thread thread = new Thread(new Runnable() {
@Override
public void run() {
loadSectionStories(sessionKey, section);
}
});
thread.start();
curatedSections.add(section);
}

}

@Override
public void onFailure(Call<JsonArray> call, Throwable t) {
Log.d("ERROR!", t.toString());
t.printStackTrace();
}
});
}

section.stories 返回 null 外,一切正常。这对我来说没有意义,因为 loadSectionStories 中的这条语句 section.stories = stories

最佳答案

如果您在同步请求完成(在新线程中运行)之前使用 section.stories,那么它将返回当前正在发生的 null。

所以如果你想在你的第一个异步请求完成后使用它,你必须删除新的线程流,

或者您必须在故事更新时重新加载回收站 View 。

还有你为什么在新线程中执行你的同步请求(loadSectionStories),这不是类似于异步请求吗?

关于android - 改造 - 如何在异步请求中发出同步请求,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/47974541/

27 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com