php - 如何使用 PHP 根据该值将具有匹配列值的 MySQL 查询结果放入关联数组？

Question

我有一个垂直模式的数据库，解释说:

Key, Cat, UID, Var, Val, 等等...其中 Key 是索引，Cat 是类别，UID 是一组行的标识符，var 是行表示的值的名称，Val 是该值。所以几行看起来像这样:

key cat   uid    var          val
 1   1   98765  name         David
 2   1   98765  description  handsome, young, sporting, 
 3   1   98765  phone        123-456-789
 4   1   98765  email        david@handsome.com
 5   1   12345  name         Jason
 6   1   12345  description  cool, hot, tall, 
 7   1   12345  phone        222-555-1244
 8   1   12345  email        jason@cool.org
 8   1   12345  website      www.jason.com

所以 query/php 的目标是从指定的类别中获取所有行，然后根据具有该 uid 的所有行的 uid 返回一个关联数组。结果会有点像

results{
["98765"] => ["name"] = David
          => ["description"] = handsome, young, sporting,
          => ["phone"] = 123-456-789
          => ["email"] = david@handsome.com
["12345"] => ["name"] = Jason
          => ["description"] = cool, hot, tall,
          => ["phone"] = 222-555-1244
          => ["email"] = jason@cool.org
          => ["website"] = www.jason.com
}

希望这是可以理解的，如果我的问题不清楚，请告诉我。

Answer 1

尝试这样的事情:

$category = 1;
$result = mysql_query( 'SELECT * FROM table WHERE cat = ' . intval( $category));
$results = array();
while( $row = mysql_fetch_array( $result))
{
    $results[ $row['uid'] ][ $row['var'] ] = $row['val'];
}
mysql_free_result( $result);