php - 复杂的 SQL 查询 JOIN 和 WHERE

Question

我有一张表，我需要从中获取联系人。所以我使用一个复杂的查询从我的“短信”表中检索所有联系人。

但是，它应该只计算提供的“imei”字段的记录，但我的查询一直返回特定联系人的所有计数。

下面是使用的代码:

$sql = $this->db->query('
    SELECT 
        t1.mnumber AS t1_number, t1.mcontent AS t1_content, t1.mcontact as t1_contact, SUM(t2.TOTAL) AS mTotal
    FROM
        sms t1
            JOIN
        (SELECT 
            mContent, mcontact, COUNT(mNumber) AS TOTAL, mnumber, MAX(mID) mID
        FROM
            sms
        GROUP BY mContact) t2 ON t1.mcontact = t2.mcontact
            AND t1.mid = t2.mid
        WHERE t1.mIMEI = ' . (IMEI) . '
        GROUP BY t1.mContact
        ORDER BY t1.mid DESC');

    return $sql->result();

Answer 1

更好的格式，查询是:

SELECT t1.mnumber AS t1_number, t1.mcontent AS t1_content, t1.mcontact as t1_contact, SUM(t2.TOTAL) AS mTotal
FROM sms t1 JOIN
     (SELECT mContent, mcontact, COUNT(mNumber) AS TOTAL, mnumber, MAX(mID) mID
      FROM sms
      GROUP BY mContact
     ) t2
     ON t1.mcontact = t2.mcontact AND t1.mid = t2.mid
WHERE t1.mIMEI = ' . (IMEI) . '
GROUP BY t1.mContact
ORDER BY t1.mid DESC

问题是 where 子句在错误的地方。为了影响计数，您需要在子查询中使用它。为了影响输出行，您需要在外部查询中使用它。我建议:

SELECT t1.mnumber AS t1_number, t1.mcontent AS t1_content, t1.mcontact as t1_contact, SUM(t2.TOTAL) AS mTotal
FROM sms t1 JOIN
     (SELECT mContent, mcontact, COUNT(mNumber) AS TOTAL, mnumber, MAX(mID) as maxmid
      FROM sms
      WHERE sms.mIMEI = ' . (IMEI) . '
      GROUP BY mContact
     ) t2
     ON t1.mcontact = t2.mcontact AND t1.mid = t2.maxmid
GROUP BY t1.mContact
ORDER BY t1.mid DESC

我怀疑可能还有其他简化，具体取决于 mid 和 mcontact 在数据库结构方面的含义。