ios - 从 didReceiveRemoteNotification 加载 Storyboard View Controller

Question

我使用了 Storyboard。该应用程序是基于标签栏 Controller 的。

单击推送通知时，我想从 Storyboard打开特定的“通知事件” View Controller 。”我不知道 didReceiveRemoteNotification 中包含哪些代码。

我的代码是:

NSString *notification = [[userInfo valueForKey:@"aps"] valueForKey:@"alert"];

Dashboard *ds = [[UIStoryboard storyboardWithName:@"Main" bundle:nil] instantiateViewControllerWithIdentifier:@"Dashboard"] ;
NotificationTable *nt = [[UIStoryboard storyboardWithName:@"Main" bundle:nil] instantiateViewControllerWithIdentifier:@"NotificationBoard"] ;

UIStoryboardSegue *segue = [UIStoryboardSegue segueWithIdentifier:@"NotificationBoardTable"
                                                           source:ds
                                                      destination:nt
                                                   performHandler:^{
                                                   }];

[ds performSegueWithIdentifier:@"NotificationBoardTable" sender:ds];

Answer 1

让我们看看这是否是您想要的:

[[NSNotificationCenter defaultCenter] postNotificationName:kReceiveNotification object:nil userInfo:YOUR_DATA_PASSING];

然后在您的自定义选项卡 View Controller 中接收它:

[[NSNotificationCenter defaultCenter] addObserver:self selector:@selector(YOUR_HANDLE_METHOD:) name:kReceiveNotification object:nil];

不要忘记在释放时移除观察者:

[[NSNotificationCenter defaultCenter] removeObserver:self];

最后在那个方法中:

[self setSelectedIndex:xxx];//If you want to switch tab