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php - 这个 'paid or unpaid invoices' MySQL 查询可能吗?

转载 作者:行者123 更新时间:2023-11-29 02:20:58 27 4
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我正在尝试生成一个将显示“已支付”发票的查询。我的查询不起作用,这意味着其中存在错误,或者我试图通过这种方式实现的目标是不可能的。

// paid

$statement = "accounts_invoice i
INNER JOIN customer_type ct on i.invoice_customer_type = ct.customer_type_id
LEFT JOIN accounts_invoice_payment ip on i.invoice_id = ip.invoice_payment_invoice_id
WHERE invoice_posted='1'
AND (i.invoice_total_amount_exc_vat + i.invoice_total_vat_amount) = ip.TotalPayments"
. $where
. " ORDER BY invoice_id DESC";

$invoice_details_query = mysqli_query($con,
"SELECT i.*, ct.customer_type_name,
ip.invoice_payment_amount AS TotalPayments
FROM {$statement}
LIMIT {$startpoint} , {$per_page}")
or die(mysql_error());

$where 字符串在这个例子中是空的,你可以删除它。您也可以删除“LIMIT”,因为它纯粹用于分页。

我只是想制作一个页面来显示已付款或未付款的发票,考虑到这在理论上听起来很简单,这让我抓狂!

数据库结构;

-- phpMyAdmin SQL Dump
-- version 4.0.10.7
-- http://www.phpmyadmin.net
--
-- Host: localhost
-- Generation Time: Aug 08, 2015 at 05:17 PM
-- Server version: 5.1.73-cll
-- PHP Version: 5.4.31

SET SQL_MODE = "NO_AUTO_VALUE_ON_ZERO";
SET time_zone = "+00:00";

--
-- Database: `propsyst_atlas`
--

-- --------------------------------------------------------

--
-- Table structure for table `accounts_invoice`
--

CREATE TABLE IF NOT EXISTS `accounts_invoice` (
`invoice_id` int(11) NOT NULL AUTO_INCREMENT,
`invoice_customer_type` tinyint(4) DEFAULT NULL,
`invoice_customer` int(11) DEFAULT NULL,
`invoice_date` date DEFAULT NULL,
`invoice_due_date` date DEFAULT NULL,
`invoice_property_id` int(11) DEFAULT NULL,
`invoice_tenancy_id` int(11) DEFAULT NULL,
`invoice_branch` int(11) DEFAULT NULL,
`invoice_payment_terms` tinyint(4) DEFAULT NULL,
`invoice_notes` text COLLATE utf8_bin,
`invoice_total_amount_exc_vat` decimal(10,2) DEFAULT NULL,
`invoice_total_vat_amount` decimal(10,2) DEFAULT NULL,
`invoice_posted` tinyint(4) DEFAULT '0',
`invoice_date_created` datetime DEFAULT NULL,
`invoice_date_updated` datetime DEFAULT NULL,
`invoice_date_posted` datetime DEFAULT NULL,
`invoice_created_by` int(11) DEFAULT NULL,
`invoice_updated_by` int(11) DEFAULT NULL,
`invoice_posted_by` int(11) DEFAULT NULL,
PRIMARY KEY (`invoice_id`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_bin AUTO_INCREMENT=87 ;


-- phpMyAdmin SQL Dump
-- version 4.0.10.7
-- http://www.phpmyadmin.net
--
-- Host: localhost
-- Generation Time: Aug 08, 2015 at 05:18 PM
-- Server version: 5.1.73-cll
-- PHP Version: 5.4.31

SET SQL_MODE = "NO_AUTO_VALUE_ON_ZERO";
SET time_zone = "+00:00";

--
-- Database: `propsyst_atlas`
--

-- --------------------------------------------------------

--
-- Table structure for table `accounts_invoice_payment`
--

CREATE TABLE IF NOT EXISTS `accounts_invoice_payment` (
`invoice_payment_id` int(11) NOT NULL AUTO_INCREMENT,
`invoice_payment_date` date DEFAULT NULL,
`invoice_payment_amount` decimal(10,2) DEFAULT NULL,
`invoice_payment_method` tinyint(4) DEFAULT NULL,
`invoice_payment_invoice_id` int(11) DEFAULT NULL,
`invoice_payment_notes` text COLLATE utf8_bin,
`invoice_payment_date_created` datetime DEFAULT NULL,
`invoice_payment_date_updated` datetime DEFAULT NULL,
`invoice_payment_created_by` int(11) DEFAULT NULL,
`invoice_payment_updated_by` int(11) DEFAULT NULL,
PRIMARY KEY (`invoice_payment_id`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_bin AUTO_INCREMENT=71 ;

-- phpMyAdmin SQL Dump
-- version 4.0.10.7
-- http://www.phpmyadmin.net
--
-- Host: localhost
-- Generation Time: Aug 08, 2015 at 05:58 PM
-- Server version: 5.1.73-cll
-- PHP Version: 5.4.31

SET SQL_MODE = "NO_AUTO_VALUE_ON_ZERO";
SET time_zone = "+00:00";

--
-- Database: `propsyst_atlas`
--

-- --------------------------------------------------------

--
-- Table structure for table `customer_type`
--

CREATE TABLE IF NOT EXISTS `customer_type` (
`customer_type_id` int(11) NOT NULL AUTO_INCREMENT,
`customer_type_name` varchar(20) COLLATE utf8_bin DEFAULT NULL,
PRIMARY KEY (`customer_type_id`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_bin AUTO_INCREMENT=4 ;

最佳答案

实际上你的查询是

SELECT
i.*,
ip.invoice_payment_amount AS TotalPayments
FROM accounts_invoice i
LEFT JOIN accounts_invoice_payment ip
ON i.invoice_id = ip.invoice_payment_invoice_id
WHERE invoice_posted='1'
AND (i.invoice_total_amount_exc_vat + i.invoice_total_vat_amount) = ip.TotalPayments
ORDER BY invoice_id DESC

并且该查询失败,因为 where 语句中的 ip.TotalPayments 是未知列。您需要使用原始名称 ip.invoice_payment_amount。别名仅用于返回的集合,而不用于查询本身。

此外,您的数据库设计还可以改进。首先,我建议使用 InnoDB 而不是 MyISAM。这允许您使用外键,因此表之间实际上存在关系。

另外,我会将 WHERE 子句的 AND 部分移至 ON 子句,如下所示:

SELECT
i.*,
ip.invoice_payment_amount AS TotalPayments
FROM accounts_invoice i
LEFT JOIN accounts_invoice_payment ip
ON i.invoice_id = ip.invoice_payment_invoice_id
AND (i.invoice_total_amount_exc_vat + i.invoice_total_vat_amount) = ip.invoice_payment_amount
WHERE invoice_posted='1'
ORDER BY invoice_id DESC

SELECT * FROM A LEFT JOIN B ON A.id = B.a_id 的结果包含 A 的每一行和 B< 的匹配行。如果 B 没有与 A 中的行匹配的行,则 B 中列的值为 NULL。如果您不希望这样,而只想要 A 的行在 B 中具有匹配行,则您应该使用 INNER JOIN

关于php - 这个 'paid or unpaid invoices' MySQL 查询可能吗?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/31895937/

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