mysql - 基于与外键的连接更新列中的数据

Question

我有一个包含一些不正确数据的表格，我想更正这些数据。例如 - 在“address_detail”表中，地址字段的前缀错误地为“null”而不是城市名称。

id | city_id | address
-----------------------------
7  |    1    | null/Street39
8  |    2    | null/Street40
9  |    3    | null/Street41
10 |    4    | null/Street42

city table 

id  | name
--------------- 
1   | Mexico    
2   | New York  
3   | Washington    
4   | Los Angeles

修正后，我希望数据是这样的:

地址明细表

id  | city_id   | address
-------------------------------
7   | 1         | Mexico/Street39
8   | 2         | New York/Street40
9   | 3         | Washington/Street41
10  | 4         | Los Angeles/Street42

我尝试了以下脚本，但出现错误。

UPDATE
    address_detail ad
SET
    ad.address = (CONCAT( SELECT name FROM city c WHERE c.id = ad.city_id, SUBSTRING( ad.address, 5 )))
WHERE
    ad.address LIKE 'null/%'

Answer 1

UPDATE
    address_detail ad
SET
    ad.address = REPLACE(ad.address, 'null', ( SELECT name FROM city c WHERE c.id = ad.city_id))
WHERE
    ad.address LIKE 'null/%'