gpt4 book ai didi

mysql - 如何检查 JOIN 的结果是否为 NULL?

转载 作者:行者123 更新时间:2023-11-29 02:13:34 25 4
gpt4 key购买 nike

这是我的表结构:

-- categories
+----+-------------+
| id | name |
+----+-------------+
| 1 | political |
| 2 | cultural |
| 3 | social |
| 4 | historical |
+----+-------------+

-- tags
+----+-------------+-----------+-------------+-----------------+
| id | name | parent_id | category_id | total_used_num |
+----+-------------+-----------+-------------+-----------------+
| 1 | president | NULL | 1 | 43 |
| 2 | society | NULL | 3 | 345 |
| 3 | Trump | 1 | 1 | 5 |
| 4 | book | 5 | 2 | 5473 |
| 5 | library | NULL | 2 | 433 |
+----+-------------+-----------+-------------+-----------------+

这是我的查询:

SELECT t1.name, 
CONCAT(t2.name, ',', cat.name) t_p
FROM tags t1
LEFT JOIN tags t2
ON t1.parent_id = t2.id
INNER JOIN categories cat
ON t1.category_id = cat.id
ORDER BY total_used_num DESC,
t1.id

/* output
+----+-------------+--------------------------+
| 1 | president | NULL |
| 2 | society | NULL |
| 3 | Trump | president,political |
| 4 | book | library,cultural |
| 5 | library | NULL |
+----+-------------+--------------------------+

看到了吗? CONCATNULL 的结果是 NULL。无论如何,我怎样才能避免这种情况?我还想让那个逗号 , 成为条件。如果两个字段都不是 NULL,那么逗号应该在那里。这是预期结果:

+----+-------------+--------------------------+
| 1 | president | political |
| 2 | society | social |
| 3 | Trump | president,political |
| 4 | book | library,cultural |
| 5 | library | cultural |
+----+-------------+--------------------------+

我该怎么做?

最佳答案

只需使用concat_ws():

SELECT t1.name, 
CONCAT_WS(',', t2.name, cat.name) as t_p
FROM tags t1 LEFT JOIN
tags t2
ON t1.parent_id = t2.id INNER JOIN
categories cat
ON t1.category_id = cat.id
ORDER BY total_used_num DESC, t1.id ;

关于mysql - 如何检查 JOIN 的结果是否为 NULL?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/45025521/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com